2007-01-26 08:23:28 · 10 answers · asked by chris 2 in Science & Mathematics ➔ Mathematics
I am a computer programmer so I would use a program to do it for me. The output it gave me was: - x^2 - 4x + 2
Oh and the program factored it further so that you can find the value of X.
It says X is equal to: -2 - SQRT 6 Or -2 + SQRT 6
Instead of PEMDAS I like to use PROGRAM. LOL.
2007-01-26 08:45:44 · answer #1 · answered by -J- 3 · 0⤊ 3⤋
Take this one term at a time. The (x-7) seems to be the inner most term. So distribute the "-" through it:
6x - (3x - [4x - (x - 7)] +12x - (2x - x^2 -5))
6x - (3x - [4x - x + 7] +12x - (2x - x^2 -5))
You can simplify what's in the brackets. 4x-x = 3x, so now we have:
6x - (3x - [3x + 7] +12x - (2x - x^2 -5))
Now get rid of the brackets. There's a minus before the brackets, so again we have to change the sign of everything inside:
6x - (3x - 3x - 7 +12x - (2x - x^2 -5))
The 3x and -3x cancel out:
6x - (0 - 7 +12x - (2x - x^2 -5))
6x - (-7 +12x - (2x - x^2 -5))
Now carry the minus through the second parentheses:
6x - (-7 +12x - 2x + x^2 + 5)
Combine the terms inside. Then finally distribute the "-" in front of the only parentheses left, and combine terms again.
6x - (-2 +10x + x^2)
6x + 2 - 10x - x^2
-4x + 2 - x^2
So put in proper polynomial form (highest to lowest with the exponents), the expression simplifies to -x^2 - 4x + 2.
I don't know why some people thought they could "solve" this for x or use the quadratic formula, since there was no equation to solve. Just an expression to simplify. I suppose you could try using the quadratic forumla to factor this out into something in the form of (-x + m)(x + n), but that would involve some messy square roots. Better to keep it as a polynomial.
2007-01-26 08:58:47 · answer #2 · answered by Anonymous · 0⤊ 2⤋
= 6x- (3x- 4x +x -7 +12x -2x +x^2 +5)
= 6x -3x +4x -x +7 -12x +2x -x^2 -5
= 2 -4x -x^2
= -(x^2+4x-2)
This can then further be simplified using the quadratic equation which I shall leave to you to solve :)
2007-01-26 08:44:55 · answer #3 · answered by samuelll 2 · 1⤊ 1⤋
start with inner most brackets frist then work your way out. This includes exponents.
a simple rule to remember
PEMDAS - Please Excuse My Dear Aunt Sally
P = Perentises
E = Exponents
M = Multipulcation
D = Division
A = Addition
S = Subtraction
example...
(x-7) would be inner most with in the set of [4x - (x-7)]
as would -(2x-x^2-5) be inside the set contained with in the parenthesis (3x -[4x-(x-7)+12x-(2x-x^2-5))
make sure to see (2x-x^2-5) as - (2x-x^2-5) because this will change everything, making it -2x + x^2 + 5 with in that particulare section, and so on as you work it out.
lets take out the varibles and coeeficiants for now to look at it more simplified...
( c [ b ( a ) ] c ( a ) )
where as the 'a''s would be inner most, 'b''s second inner most and 'c''s third inner most and so on. This is basic order of opperations.
*added, I will not do your homework for you, but alittle hint, Bill F got it right! A parenthesis () brace {} or bracket [] does not matter, they are only used to help distingush between ordered sets to help you quickly find which one lays in what set to come first and so on. You could use all parenthesis if you wanted, however it would just make things alittle harder to find sets.
Study alittle Boolean, its fun
2007-01-26 08:33:11 · answer #4 · answered by dee 'the harpoon' harper 3 · 0⤊ 1⤋
Use PEMDAS > ( ), exponents, multiplication, division, addition and subtraction...
6x - (3x - [4x - x - (-7)] + 12x - (2x - x^2 -5))
6x - (3x - [4x - x + 7] + 12x - (2x - x^2 -5))
6x - (3x - [3x + 7] + 12x - (2x - x^2 -5))
6x - (3x - 3x -7) + 12x - (2x - x^2 -5))
6x - (-7) + 12x - (2x - x^2 -5))
6x + 7 + 12x - (2x - x^2 -5))
6x + 7 + 12x - 2x - (-x^2) - (-5)
6x + 7 + 12x - 2x + x^2 + 5
Sec: combine "like" terms...
x^2 + 16x + 12
2007-01-26 11:28:15 · answer #5 · answered by ♪♥Annie♥♪ 6 · 0⤊ 1⤋
Use PEMDOS, combine like terms
1st
6x-(3x-[4x-x+7]+12x-2x+x^2+5
2nd
6x-(3x-4x+x-7)+12x-2x+x^2+5
3rd
6x-3x+4x-x+7+12x-2x+x^2+5
4th
16x+x^2+12
5th
x^2+16x+12
hope it helps! and do check to see if i made mistakes
2007-01-26 08:43:55 · answer #6 · answered by Anonymous · 0⤊ 1⤋
6x - (3x - [4x - (x - 7)] +12x - (2x - x^2 -5))
6x - (3x - [4x - x + 7)] +12x - 2x + x^2 + 5)
6x - (3x - 4x + x - 7) +12x - 2x + x^2 + 5
6x - 3x + 4x - x + 7 +12x - 2x + x^2 + 5
x^2 + 17x + 12
2007-01-26 08:33:28 · answer #7 · answered by Bill F 6 · 1⤊ 1⤋
Simplifying
6x + -1(3x + -1[4x + -1(x + -7)] + 12x + -1(2x + -1x2 + -5))
Reorder the terms:
6x + -1(3x + -1[4x + -1(-7 + x)] + 12x + -1(2x + -1x2 + -5))
6x + -1(3x + -1[4x + (-7 * -1 + x * -1)] + 12x + -1(2x + -1x2 + -5))
6x + -1(3x + -1[4x + (7 + -1x)] + 12x + -1(2x + -1x2 + -5))
Reorder the terms:
6x + -1(3x + -1[7 + 4x + -1x] + 12x + -1(2x + -1x2 + -5))
Combine like terms: 4x + -1x = 3x
6x + -1(3x + -1[7 + 3x] + 12x + -1(2x + -1x2 + -5))
6x + -1(3x + [7 * -1 + 3x * -1] + 12x + -1(2x + -1x2 + -5))
6x + -1(3x + [-7 + -3x] + 12x + -1(2x + -1x2 + -5))
Reorder the terms:
6x + -1(3x + -7 + -3x + 12x + -1(-5 + 2x + -1x2))
6x + -1(3x + -7 + -3x + 12x + (-5 * -1 + 2x * -1 + -1x2 * -1))
6x + -1(3x + -7 + -3x + 12x + (5 + -2x + 1x2))
Reorder the terms:
6x + -1(-7 + 5 + 3x + -3x + 12x + -2x + 1x2)
Combine like terms: -7 + 5 = -2
6x + -1(-2 + 3x + -3x + 12x + -2x + 1x2)
Combine like terms: 3x + -3x = 0
6x + -1(-2 + 0 + 12x + -2x + 1x2)
6x + -1(-2 + 12x + -2x + 1x2)
Combine like terms: 12x + -2x = 10x
6x + -1(-2 + 10x + 1x2)
6x + (-2 * -1 + 10x * -1 + 1x2 * -1)
6x + (2 + -10x + -1x2)
Reorder the terms:
2 + 6x + -10x + -1x2
Combine like terms: 6x + -10x = -4x
2 + -4x + -1x2
2007-01-26 09:04:28 · answer #8 · answered by Anonymous · 0⤊ 2⤋
6x - (3x - [4x - (x - 7)] +12x - (2x - x^2 -5))
6x-3x-4x-x-7+12x-2x-x^2-5
8x-7-x^2-5
x^2+8x-12
(x-6)(x+2)
2007-01-26 09:05:36 · answer #9 · answered by ? 3 · 0⤊ 2⤋
x^2+15x-2
2007-01-26 08:37:45 · answer #10 · answered by Anonymous · 0⤊ 1⤋