I got something totally different from the other responses. My arithemetic may be off, but I will include the basic rules to help you gain more understanding.
lets start with the top. (-2x^2y^5)^3 (4xy)^-2.
Anytime you have a power raised to a power, you multiply powers
-2^3= -8
(x^2)^3 = x^6
(y^5)^3 = y^15
So the first part is -8x^6y^15
Anything raised to a negative power switches from top to bottom, so (4xy)^-2 goes to the denominator. So we are finished with the numerator for now.
Denominator...You have (4xy)^2 from the top (once you move, the negative on the power becomes positive) times -x^2y^-2
-x^2 stays the same (it would only be pos if the -x was in parentheses) and y^-2 moves that up to the numerator.
So in your denominator you have ((4xy)^2)(-x^2)
Now time to simplify. Numerator is -8x^6y^15 (y^2)--(from the denom). When you are multiplying powers, you add, so the numerator simplifies to -8x^6y^17
Denom... ((4xy)^2) simplifies to 16x^2y^2, plus multiplied by the -x^2, you get -16x^4y^2.
Now numerator ----> -8x^6y^17
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denom -----> -16x^4y^2
to simplify exponents when you are dividing, subtract them. The negatives cancel,
1 x^2 y^15
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2
Solution is (x^2y^15)/2
or you can say 1/2 (x^2.y^15)
2007-01-26 08:36:39
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answer #1
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answered by prudentzeta 2
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We have
(-2x^2.y^5)^3 = -8.x^6.y^15
(4xy)^-2 = 1 / (16.x^2.y^2)
1/ ( -x^2y^-2) = - y^2 / x^2
so the whole thing is
-8.x^6.y^15 x 1 / (16.x^2.y^2) x (-y^2 / x^2)
Counting the powers of x gives 6-2-2 = 2
Counting the powers of y gives 15 - 2 - 2 = 11
8 divides into 16 to give 2
The -'s cancel
So it simplifies to (x^2).(y^11)/2
Why do you need to know?
2007-01-26 08:24:53
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answer #2
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answered by Always Hopeful 6
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Well, you can't use a computer program on a test, so rewrite this so that it is easily cancellable.....
(-2xx2yyyyy) (write this one out three times)
(is the second term to the -2 power? then it is 1/over 4xy4xy... make the lines straight with a distinct numerator and denominator... slanted lines are confusing
the denominator is (-x)(-x) and the 2y to the neg. 2 power is / over 2yy.
your entire expression is all one term,(no + or - sign outside a set of parenthesis) so you can cancel, ys top and bottom neg signs top and bottom each x matching top and bottom.
After you get the hang of this, you won't have to write it all out, but when entire expressions are squared, or raised to neg. powers, this is often the most efficient way to do it, and get the right answer... The trick??? be neat with your writing....tuff, I know...
2007-01-26 08:34:35
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answer #3
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answered by April 6
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Hopefully, I'm interpreting it right.
Then answer is (x^2y^15)/2
(-2x²y5)³(4xy)-2 =
-x2y-2
(-2x2y5)3 y2
-x2(4xy)2
-8x6y15y2
-x216x2y2
8x6y17
16x4y2
x2y15
2
2007-01-26 08:56:01
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answer #4
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answered by elise_dreamer_95 2
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those are in reality an analogous subject. interior the 1st, element out a three from the two numerator and denominator. 3x+6 = 3(x+2) 3x-6 = 3(x-2) Then the quotient = 3(x+2) / 3(x-2) = 3/3 * (x+2)/(x-2) = a million * (x+2)/(x-2) = (x+2)/(x-2) the 2nd works an analogous way. you're able to be able to desire to come again to a determination what quantity to element out.
2016-12-12 21:00:27
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answer #5
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answered by Anonymous
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(-2x^2y^5)^3 (4xy)^-2 / [-x^2y^-2]
= (1/2) x^(6-2-2) y^(15-2+2)
= (1/2)(x^2)(y^15)
2007-01-26 08:20:52
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answer #6
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answered by sahsjing 7
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-4x^2 y^15
2007-01-26 08:22:55
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answer #7
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answered by Anonymous
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thats a hard one GOOD LUCK!! I'll pray for you. LOL
2007-01-26 08:18:48
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answer #8
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answered by Airen 2
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i shitted myself looking at it
______________________
good luck to you with it!!!!
2007-01-26 08:21:26
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answer #9
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answered by Anonymous
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