6√2x^2 - 3√18x^2
= 6|x|√2 - 9|x|√2
= -3√2 |x|
2007-01-26 08:15:02
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answer #1
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answered by sahsjing 7
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6â2x^2 - 3â18x^2 18=3*3*2
6xâ2 - 9xâ2
- 3â2
2007-01-26 16:17:25
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answer #2
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answered by matthewjc314 3
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Simplify the expression: 6â2x^2 - 3â18x^2
First: express terms (in the radical signs) without exponents....
6â2(x)(x) - 3â3*3*2(x)(x)
Sec: when you have a number & variable repeated twice, you can write it once in front of the radical sign...
6xâ2 - 3(3)xâ2
6xâ2 - 9xâ2
Third: you have the same radical number > "2" > subtract the coefficients...
- 3xâ2
2007-01-26 23:41:54
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answer #3
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answered by ♪♥Annie♥♪ 6
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-3xâ2 = 6â(2x^2) - 3â(18x^2)
2007-01-26 16:16:23
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answer #4
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answered by icthyus05 3
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I agree with the second answer of -3xâ2 (Since both x are squared you can bring them outside of the square root. Factor 18 to 9x2 and bring the square root of nine outside as well. so it's 6xâ2 - (3*3xâ2) or 6xâ2 -9xâ2. That gives you -3xâ2)
2007-01-26 16:21:02
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answer #5
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answered by elise_dreamer_95 2
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what???????????????????????? im in honors math and dont even know what the heck that is! lol hope u get the answer correct
good luck :)
2007-01-26 16:15:44
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answer #6
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answered by Anonymous
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6x*sqrt(2)-9x*sqrt(2)=-3x*sqrt(2)
2007-01-26 16:15:49
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answer #7
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answered by bruinfan 7
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