2007-01-26 07:55:57 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The Correct formula is 2*2007-1 (NOT + 1)...so your answer would be 4013!
2007-01-26 08:03:53 · answer #1 · answered by Dennis L 2 · 0⤊ 0⤋
The 2007th positive integer is 2007.
The first odd positive integers, in order, are 1, 3, 5, 7, ... They are always spaced by 2 units, so its general form is
odd(n) = 1 + 2(n - 1) = 2n - 1
Check it for several values of n; if you can, prove the validity of the formula by induction (see sources).
So, the 2007th odd positive integer is odd(2007) = 4013.
2007-01-26 16:08:34 · answer #2 · answered by jcastro 6 · 1⤊ 0⤋
To get the nth positive odd integer, the formula would be 2n - 1.
In your case, it would be 2(2007) - 1, or 4014 - 1, or
4013.
Note that this works for the first odd positive integer;
If n = 1, then 2(1) - 1 = 2 - 1 = 1.
Therefore, the formula is indeed 2n - 1 instead of 2n + 1.
2007-01-26 16:00:35 · answer #3 · answered by Puggy 7 · 1⤊ 0⤋
It's 2*2007 + 1 = 4015
2007-01-26 15:59:46 · answer #4 · answered by Pfo 7 · 0⤊ 1⤋
4015
2007-01-26 16:15:51 · answer #5 · answered by onyx200050 3 · 0⤊ 0⤋