2007-01-26 07:39:45 · 5 answers · asked by chris 2 in Science & Mathematics ➔ Mathematics
11 is the square root of 121, so....
11x^12
If the x^12 portion is under the radical also, then
11x^6
since x^6 is the square root of x^12
2007-01-26 07:44:45 · answer #1 · answered by MamaMia © 7 · 0⤊ 0⤋
Did you mean sqrt(121 * x^12)? (everthing under the square root symbol)
If so, note that sqrt(b) = b^(1/2), by definition, and use several properties of exponents (more information about them in the sources below):
(121 * x^12)^(1/2) =
(121)^(1/2) * (x^12)^(1/2) =
(11^2)^(1/2) * x^(12*1/2) =
11^(2*1/2) * x^6 =
11 * x^6
2007-01-26 16:03:08 · answer #2 · answered by jcastro 6 · 0⤊ 0⤋
I guess x^12 is under the square root right? So you get 11 x^6, and don't listen to those silly boys who are trying to confuse you.
2007-01-26 15:47:40 · answer #3 · answered by gianlino 7 · 0⤊ 0⤋
No, it can't be done. If a mathmetician tells you it has been solved, they're obviously cheating with made-up notions of "square roots" and such.
2007-01-26 15:45:40 · answer #4 · answered by lenoxus 3 · 1⤊ 0⤋
11x^6
2007-01-26 15:46:36 · answer #5 · answered by Anonymous · 0⤊ 0⤋