How many grams of nicotine (C10H14N2)contain 18.0 g H?
mass C10H14N2 = __________g
2007-01-26 07:05:59 · 2 answers · asked by beachbum 2 in Science & Mathematics ➔ Chemistry
Well there is 14 g H in 1 mole of nicotine 162 g/mole
use a simple proportion to get 208.3 g nicotine
2007-01-26 07:18:22 · answer #1 · answered by Dr Dave P 7 · 0⤊ 0⤋
this is a problem best done by dimensional analysis or factor label method
start by converting the 18.0 g H to mole H
18.0 g H x (1 mole H / 1.01 g H) = 17.8 mole H
then convert the 17.8 mole H to mole of nicotine and the formula of nicotine tells you that there are 14 moles of H in 1 mole of nicotine
17.8 mole H x (1 mole nicotine / 14 mole H) = 1.27 mole nicotine
then convert the moles of nicotine to grams of nicotine using the molar mass of nicotine
1.27 mole nicotine x (162.1 g nicotine / 1 mole nicotine) = 205.9 g of nicotine is your final answer
2007-01-26 15:25:07 · answer #2 · answered by chem geek 4 · 0⤊ 0⤋