how can you get a .70% acidic solution to give you 22% acidic solution!!!!????
2007-01-26 06:14:53 · 4 answers · asked by harry p 1 in Science & Mathematics ➔ Mathematics
Can you add 100% pure acidic solution to it?
If you meant to say 70% (and not .70%), then you would need to dilute it. Maybe you could add water to it?
2007-01-26 06:22:50 · answer #1 · answered by MsMath 7 · 2⤊ 1⤋
I am assuming you mean a 70% acidic solution, not a 0.70% solution, which would be virtually impossible (without adding a higher concentration of acid!)
So you need to know at what ratio to dilute 70% acid to make the solution 22% acid.
Let's let x = the total volume of a 22% acidic solution, and y = the total volume of inert material.
.22x = .7(x-y)
.22x = .7x - .7y
.7y = .48x
y = .68571 or 68.571% neutral solution
so if you mix 70% acidic solution as 31.429% and a neutral (water) at 68.571% of the total solution you will get 22% acidic solution.
2007-01-26 06:30:08 · answer #2 · answered by disposable_hero_too 6 · 0⤊ 0⤋
you will have to boil the solution.s g of the say you have 100 g of the acid, you have to have a final weight 0f 3.18g of the soln in order to get a 22% concentration
2007-01-26 06:39:17 · answer #3 · answered by supermontero2000 2 · 0⤊ 0⤋
hmm, maybe you can look for an online tutor in math, its really cheap if you search for them located in india.
2007-01-26 06:23:27 · answer #4 · answered by Jeannie 3 · 0⤊ 0⤋