We know,
density=mass/volume
Here the dimensions of the rectangular block are 1.2*2.1*1.1 cm
So the volume will be=1.2*2.1*1.1=2.772cm^3 or 2.772 cc
Here given, The mass of the block is 23.6 gm.
Therefore the density will be=(23.6/2.772) gm/cm^3
=8.5137 gm/cm^3 [ in C.G.S ]
or 8513.7 kg/m^3 [ in S.I or M.K.S ]
2007-01-26 05:43:10
·
answer #1
·
answered by sharbadeb 2
·
1⤊
0⤋
Density is mass/volume. The mass is given.
The volume is the product of the 3 dimensions.
So the density = 23.6/(1.2*2.1*1.1) = 23.6/2.772 = 8.514 g/cc
My handbook shows iron at about 7.87, but if your numbers are right, then 8.514 is right........
2007-01-26 05:11:37
·
answer #2
·
answered by Steve 7
·
1⤊
0⤋
density (d) = mass (m) / volume (v)
GIVEN
mass of iron bock = 23.6 g
volume of block = 1.2*2.1*1.1 cubic centimetre = 2.772 cubic centimetre
Density = 23.6 / 2.772 = 8.514 gram /cubic centimetre
but how dimensions are 1.2*2.1*1.1cm i think it is (cubiccentimetre)
2007-01-26 05:40:23
·
answer #3
·
answered by Anonymous
·
1⤊
0⤋
Density=mass/volume
volume= Length*Width*Height
so 23.6/2.772 = 8.5 g/cm
2007-01-26 05:16:51
·
answer #4
·
answered by Dice 1
·
1⤊
0⤋
As New Horizons approached Pluto, it more desirable the precision interior the size of both factors had to calculate the mass through technique of Kepler's regulations: the sidereal era of the Pluto-Charon orbit and the separations of Pluto and Charon from their mutual barycenter. With that performed, a much better perfect estimate of the various of Pluto and Charon grew to grow to be attainable. the subsequent precise length of their radii made attainable more desirable perfect estimates of their user-friendly densities, which allowed more desirable perfect estimates of the ice- and rock-fractions for each body. The calculation is going like this. enable subscript a million denote Pluto. enable subscript 2 denote Charon. d is the realm to the Pluto-Charon barycenter. P is the sidereal era. M is mass. R is radius. d? = 2035 km d? = 17536 km P = 6.387230 days = 551856.7 sec G = 6.67384e-11 m³ kg?¹ sec?² M?+M? = 4?²(d?+d?)³/(GP²) = a million.45603e22 kg M? = (M?+M?) d? / (d?+d?) = a million.3046e22 kg M? = (M?+M?) d? / (d?+d?) = a million.5140e21 kg R? = 1186000 m ?? = 3M?/(4?R?³) = a million.867 g cm?³ R? = 603500 m ?? = 3M?/(4?R?³) = a million.644 g cm?³ b = density of rock = 3 g cm?³ a = density of ice = a million g cm?³ fraction ice through technique of quantity = (b??)/(b?a) = (3??)/2 ? Pluto: 0.5665 ? Charon: 0.6778 fraction ice through technique of mass = a(b/? ? a million)/(b?a) = (3/? ? a million)/2 ? Pluto: 0.3034 ? Charon: 0.4122 If that grew to grow to be into performed precise, then Pluto likely has a rocky center with a 897.6 km radius, overlaid through technique of an icy shell of 288.4 km thickness. And Charon has a rocky center with a 413.7 km radius, overlaid through technique of an icy shell of 189.8 km thickness. I saved the stunning kind of the density calculation seen in case someone desires to modify the values of a and b. Methane ice has a density of a pair of million.35 g cm?³ and nitrogen ice has a density of a pair of million.25 g cm?³ at Pluto temperatures. Water ice's density is about 0.ninety 4 g cm?³. %. the blend of water, nitrogen, and methane ices that you imagine of is the staggering one, parent its density, and assign that value to a. more desirable, in line with probability you imagine of there's a small metal center interior the rocky center, which may advance the price of b. (Earth's moon's user-friendly density is 3.34 g cm?³ because of the very actuality it has a metal inner center.) Then refigure the fractions of ice for Pluto and for Charon through technique of mass and through technique of quantity.
2016-10-16 03:34:56
·
answer #5
·
answered by Anonymous
·
0⤊
0⤋
Density is mass/volume
Volume is 1.2*2.1*1.1 cm^3
Units of the density will be g/cm^3.
Or perhaps you should change mass to kg and dimension units to meters:
Mass is .023 kg
Volume is .012*.021*.011 m^3
In this case units of the density will be kg/m^3.
2007-01-26 05:12:22
·
answer #6
·
answered by sojsail 7
·
0⤊
0⤋
V=1.2*2.1*1.1=2.772 cm3
M= 23.6
d= M/V = 23.6/2.772 = 8.513 g/cm3
density = 8.513 g/cm3
2007-01-26 05:13:01
·
answer #7
·
answered by ensar 1
·
0⤊
0⤋
density is nothing but mass/volume........so mass is 23.6g and volume is 1.2 * 2.1 * 1.1 = 2.772...................therefore density is 23.6/2.772 = 8.5137gm/cubic centimeter or in SI system it is 8513.7 kg/ cubic meter
2007-01-26 05:34:40
·
answer #8
·
answered by Aliasgar 1
·
0⤊
0⤋
d = m/V
d = m/ L*W*H
d = 23.6 / (1.2*2.1*1.1) g/cm^3
calculator.
2007-01-26 05:07:17
·
answer #9
·
answered by bequalming 5
·
0⤊
0⤋
density=mass/volume
mass=23.6g
vol=1.2*2.1*1.1
density=23.6/(1.2*2.1*1.1)
density=8.513gram/cm^3
2007-01-26 05:22:53
·
answer #10
·
answered by Anonymous
·
0⤊
0⤋