Change the equations to y-intercept form, which is:
y = mx + b
then b is your y-intercept.
Of course, you are looking for both y-intercept and x-intercept, which is easy to calculate. The y-intercept is the value of y where the line crosses the y axis, or when x = 0.
So put x = 0 to find the y-intercept, and y = 0 to find the x-intercept:
x-3y = 6
(x=0) -3y = 6, y = -2 = y-intercept
(y=0) x = 6 = x-intercept
This approach can be used on the other equations as easily!
5/7x + 6/7y = -2
6/7y = -2, y = -7/3
5/7x = -2, x = -14/5
y = -3 (this one is a little tricky)
y = -3 is the x-intercept
this equation will never cross the y-axis! So there is no x-intercept
x = -3 (same as above)
x = -3 is the y-intercept, there is no x-intercept
y+2 = 0 (just like above)
y = -2 = x-intercept, there is no y-intercept
x-3y = 0
x = y = 0 = both y and x-intercept
4y = 3x (same as the previous one)
x = y = 0 = both y and x-intercept
3y = -4/3x (same as two previous)
x = y = 0 = both the y and x-intercept
Hope this helps! :)
2007-01-26 05:00:40
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answer #1
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answered by disposable_hero_too 6
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In all of these problems to find the X intercept, you plug "0" in for Y and solve for X. That will tell you at what point the graph crosses the X axis. The opposite applies for the Y intercept. You plug in "0" for X and solve for Y. That tells you where the graph crosses the Y axis.
For example x-3y=6. To get the Y intercept, you insert "0" for X. You will get 0-3y=6 which is -3y=6 which is y=6/-3 which is y=-2. The Y intercept is (0,-2)
If there is no X in a formula or no Y, then the answer is whatever the other equals.
For example in the problem x= -3, since there is no Y in the formula, your X intercept *IS* -3 (This is where the graph will cross the X axis.)
Hope this helps!
2007-01-26 13:06:53
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answer #2
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answered by Michelle M 2
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You are going to need to "build" yourself a chart to find out what 'Y' will be when 'X' equals a certain number (chosen by you). Plot them.
I used to start with value of -5 to 5 for 'X', plug each one of these values individually into the problem for 'X', get your 'Y' answer, and place them across from that particular 'X' value in my chart:
X | Y
------|------
-5 |
-4 |
-3 |
-2 |
-1 |
0 |
1 |
2 |
3 |
4 |
5 |
----- |-------
sometimes you have to use many more negative or positive numbers than this to see where they cross the axis, but you can get the basic idea.
You could also pick the numbers for the 'Y' value and then plug them into your chart to get 'X' values and then chart them that way. Either way it works.
2007-02-01 21:07:02
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answer #3
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answered by momof5 1
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when youre looking for the x intercept, substitute the y for 0. when youre looking for the y intercept, substitue the x for 0. for example, x-3y=0. substitute x for 0: 0-3y=0 ---> -3y=0 ---> divide both sides by -3---> -3y/-3=0/-3 or y=0. do the same for x. hope u can understand that.
2007-01-26 13:03:56
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answer #4
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answered by miss_renaenae 2
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To find the x-intercept, plug in y=0. To find the y-intercept, plug in x=0. If you get an impossible result (suck as plugging x=0 into x=-3), that line is parallel to the axis in question.
2007-01-26 13:00:17
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answer #5
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answered by Chris S 5
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I do!
2007-01-26 12:59:19
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answer #6
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answered by Wounded duckmate 6
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