I will graduate college in 2 years and am more then ready to get out of Wisconsin, where i've lived almost my entire life. I am starting to think of where I want to move to.
What is your favorite, but affordable city in the U.S to live in? No like L.A or San Diego, I know I will not be able to afford to live there.
Safety is my #1 priority, and I want to get out of the Midwest. But don't want to live down south (I was born in Florida and lived there till I was 8).
2007-01-26 03:59:51 · 5 answers · asked by Vannah 1 in Business & Finance ➔ Renting & Real Estate
SEATTLE WA, EVERYTHING YOU NEED!! BEST CITY IN THE US!!!
2007-01-26 07:03:01 · answer #1 · answered by CEESONE 4 · 0⤊ 1⤋
Come to Arizona! Chandler, Mesa, Tempe, Scottsdale. It's alot more affordable than California. I have friends from WI. that lived here for a couple of years. They've sinced moved back but they miss the weather, which is awsome all year around.
2007-01-26 04:17:56 · answer #2 · answered by Claudia M 2 · 0⤊ 1⤋
Most cities are unaffordable. To save a buck you should move to a neighboorhood outside the city but still in close proximity. It really depends on your preference. In my opinion you should go to a place where there are plenty of jobs. I live in NY and there is something here for everyone. NYC is great but very expensive, you can live outside NYC and still be a subwayride away and get a bigger bang for your buck.
2007-01-26 06:22:21 · answer #3 · answered by tianaramal 4 · 0⤊ 2⤋
Move to Las Vegas.
There is a wonderful life here full of opportunity and you never have to see the "glitz" of the strip if you don't want to.
Suburban metropolis, quiet & remote areas, sprawling mountains, amazing views, awesome hiking, boating nearby, skiing nearby, employment, great entertainment, great restaurants, family friendly, single friendly.
2007-01-26 04:47:13 · answer #4 · answered by ☼High☼Voltage☼Blonde☼ 4 · 0⤊ 1⤋
Still Florida, especially small cities like Cape Coral, is a good place to live:)
2007-01-26 04:17:14 · answer #5 · answered by angel 2 · 0⤊ 2⤋