taking graph from F(x)= square root of x to g(x)= negative square root of x-8
I know it is going to shift the graph to the right 8 units, but would it be a reflection across the x-axis or the y-axis and why??
2007-01-26 03:17:43 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
If you graph the equation f(x) = sqrt(x) for x > 0, it goes through points:
(0,0),(1,1),(4,2),(9,3) and is half of a parabola whose axis is the x-axis and which lies in the upper right quadrant.
If you graph the equation g(x) = -(sqrt(x-8)) it goes through points
(8,0),(9,-1),(12,-2),(17,-3) and is half of a parabola whose axis the x-axis and which lies in the lower right quadrant.
The second curve is the first curve
f(x) = sqrt(x)
moved to the right 8 units which would be the function
h(x) = sqrt(x-8)
and then reflected through the x-axis to the function
g(x) = -(sqrt(x-8)).
The points on h(x) and g(x) would be reflections of each other through the x-axis.
The two curves f(x) and g(x) are not reflections of each other through either axis or any other line in the plane.
2007-01-26 07:35:25 · answer #1 · answered by bjs820 2 · 0⤊ 0⤋
It would be a reflection across the x-axis (along with a translation of 8 units), because you've changed the sign of y. If you changed the sign of x, it would reflect across the y-axis.
2007-01-26 11:25:38 · answer #2 · answered by Chris S 5 · 0⤊ 0⤋
cheater.do your own homework
2007-01-26 11:24:58 · answer #3 · answered by the man 3 · 0⤊ 0⤋