A 5kg object is released from a resting hieght of 12m on a curved frictionless ramp, at the bottom of the ramp is a spring with a force constant of 150 N/m. the object slides down the ramp and compresses the spring to point z on the spring before coming to rest.
Find Z
DOes the object continue to move after it comes to rest?
If yes how far will it go up the slope before coming to rest?
2007-01-26 02:19:26 · 2 answers · asked by ??? 4 in Science & Mathematics ➔ Physics
Potential energy of the object changes to kinetic energy of the object and then finally gets converted to the spring energy. The object will oscillate.
PE=mgh
PE(of spring)=.5 k z^2
z=sqrt(2mgh/k)
z=sqrt(2x5x9.81x12/150)=2.8m (corrected thanks to Steve)
How far up the slope depends on the geometry and it was not supplied. However if attached it's amplitude will be 0.89m back and forth ;-)
Thank you Steve
2007-01-26 03:20:39 · answer #1 · answered by Edward 7 · 0⤊ 0⤋
Edward forgot the g in his 3rd equation
Z = â(2*5*9.8*12/150) = 2.80 m
Since there is no friction, and hence no energy loss, the object will go back to where it started at the top of the ramp.
Still wondering what the significance of the curve in the ramp is...?
2007-01-26 05:46:32 · answer #2 · answered by Steve 7 · 0⤊ 0⤋