Trig help (check my answers)?

Question

1. A golfer takes two putts to get his ball into the hole once he is on the green. The first putt displaces the ball 6.50 m east, the second 3.00 m south. What displacement would have been needed to get the ball into the hole on the first putt?

I got 7.159 m as my answer.

2. A person walks 25.0° north of east for 2.80 km. How far would the person walk due north and due east to arrive at the same location?

I got 1.183 km for North and 2.538 km for East.

3. A girl delivering newspapers covers her route by traveling 10.00 blocks west, 4.00 blocks north, and then 5.00 blocks east.

(a) What is her resultant displacement?

Im not entirely sure about this, I believe resultant displacement is the hypotenuse? If it is I got 6.403 blocks for my answer.

(b) What is the total distance she travels?

I got 19 blocks for this.

Answer 1

2 and 3 are correct but 1 is missing some information therefore is unsolvable.

The hyp. of the triangle is 7.159 to answer one. The problem with the question is that it says that he took two putts to put the ball in the hole and then says the first putt missed and is 6.5 m to the east and the second putt misses 3 m to the south. The second put should not have displaced at all. I do see where are going with the question but the real problem is, who the hell is putting to miss by 3 m ? Happy Gilmore.

By the way Dullorb, pythagorean theorum is a part of Trig.

Answer 2

the first component to ask your self is does you answer make experience, continuously a strong component to do surprisingly in attempt circumstances. once you draw the photo you sould at present have an concept of the attitude and the gap. This guy walked 6 miles NW and then yet another 2 miles N. What you've listed less than are 2 aspects shorter aspects of a triangle. meaning the gap traveled should be between 6 and eight miles. start up by technique of drawing a photo of the problem on a grid with the drop-off aspect contained in the woods on the muse. you've one line 6 lengthy and 50 ranges up from the adverse x-axis. Then a line linked to the end 2 lengthy going instantly up. connect a line from the end of the second one line to the muse and that is what you're searching for. My suggestion is to attraction to a line down from both-mile line to the x-axis. What you should work out is a correct triange with a 50 degree attitude. you should use sin and cos formula to locate how far alongside the x-axis the triange is going and how far up the y-axis the imaginary line is going. you should use the Pythagarian theorem to locate the length of the line you try to get (that's longer than 4.fifty six miles and is in reality longer than 6 miles). you should use an inverse tan formula to also figure out the attitude. Use a photo although, it makes a lot extra experience. i'm getting 7.sixty 4 miles far and 30.3 ranges East of South One difficulty consisting of his answer is at the same time as he contraptions sin 50 ranges equivalent to (2 + y)/6. in case you seem on the diagram that I urged you to attraction to, the right triangle you should work out has 50 ranges on the muse, the imaginary line going to the point the position he hit the line and the hypotenous be the 6 mile line. Therfore it would in user-friendly words be sin(50) = y/6 and y=6sin(50)=4.60. for this reason he travelled 4.60 miles north contained in the unique 6 mile walk. Then he hit the line and go back and forth yet another 2 miles north. In finished he walk 6.60 miles north and three.86 miles west. it is your legs of the triangle, so the hypotenous (and the gap the kidnapers took him) is 7.64mi.

Answer 3

1 isn't missing any information. The answerer didn't realize that from east to south is 90 degrees.

In fact you don't need trig, the pythagorean theorum a^2+b^2=c^2 will do just as well.