2007-01-26 01:17:23 · 5 answers · asked by Rajat R 1 in Science & Mathematics ➔ Mathematics
Set up two equations for the point (x,y) that you are looking for.
Distance 5 from (7,9) means:
(x-7)² + (y-9)² = 25
Distance 1 from (3,5) means... You now have two equations, solve for x and y.
EDIT: Before doing this, check whether a solution is possible. The distance between (7,9) and (3,5) is sqrt(4²+4²)=sqrt32. If this distance were greater than 5+1=6, there would be no solution. If it were smaller than 5-1=4, there would also be no solution. This is because of the Triangle Inequality.
But sqrt32 is somewhere between 5 and 6, so you can go on solving, knowing that you will find a solution (two, in fact). Graphically, you would draw a circle of radius 5 around (7,9) and a circle of radius 1 around (3,5) and look for intersections.
2007-01-26 01:25:34 · answer #1 · answered by Anonymous · 1⤊ 0⤋
plot the points on a graph with squared paper.
then use a compass that is 5 squares apart, draw the circle round point (7,9) and 1 square for point (3,5)
where they cross will be the point.
2007-01-26 09:47:55 · answer #2 · answered by Jen 2 · 0⤊ 0⤋
you can solve this equn.
(x-7)^2+(y-5)^2=25
(x-3)^2+(y-5)^2=1
sorry i cant solve them
2007-01-26 09:27:03 · answer #3 · answered by kater al nada 2 · 0⤊ 0⤋
(4,5) is one of the points.
2007-01-26 09:54:35 · answer #4 · answered by gianlino 7 · 0⤊ 0⤋
Its not possible
2007-01-26 09:29:01 · answer #5 · answered by sunny k 1 · 0⤊ 1⤋