Yes. Neglecting air resistance, this has nothing to do with how heavy the objects are. Gravity accelerates all objects toward the earth's center at the same rate: 9.81 m/s^2.
Over the distance between your hand and the floor, air resistance would play a negligible role, so you can safely assume that they will hit the floor simultaneously.
2007-01-26 06:24:27
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answer #1
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answered by Anonymous
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The Earth's gravitational pull is a constant, so all objects, regardless of mass, fall at the same rate.
If you added air to the equation, then an object that is less streamlined (for instance, a piece of paper) will fall more slowly, because it does not cut through the air as well as, say, a pen.
And even with air, weight DOES NOT MEAN ANYTHING. If you took a brick wall and turned it on its side and dropped it beside a bowling ball, the ball would hit the ground first, because the wall covers more area, and therefore has to disperse more airflow.
2007-01-26 00:50:55
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answer #2
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answered by MannPower 4
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All objects are falling at the same rate. Because g=9,81m/s^2. You can drop a weight of 1 ton and a feather which has a few gramms, they will touch the surface at the same time.
2007-01-26 01:02:02
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answer #3
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answered by Skywalker 3
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The Earth's gravitational pull is a relentless, so all gadgets, in spite of mass, fall on the comparable cost. in case you further air to the equation, then an merchandise this is far less streamlined (case in point, fairly paper) will fall extra slowly, because of the fact it does no longer cut back contained in the path of the air besides as, say, a pen. and regardless of air, weight does no longer propose something. in case you took a brick wall and grew to become it on its section and dropped it beside a bowling ball, the ball might hit the floor first, because of the fact the wall covers extra section, and subsequently has to disperse extra airflow.
2016-09-28 00:25:53
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answer #4
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answered by carol 4
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YES!! If they are free falling, the gravity is constant and the velocity is constant. This is physics!
However, you can only test this theory without when sucking all the air in the room or neglicting air resistance!!! (that's why if you take a bowling ball and pen... due to air resistance the B.B. will fall faster. also i.e. with bowling ball and feather. You know how feather stay in the air longer)
I hope this helps ^_~
2007-01-26 00:50:16
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answer #5
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answered by Anonymous
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No because of how gravity works on an object for example a bowling ball would hit the floor before the pen (because it's heavier)
In other words an item thats (alot) heavier will drop first.
2007-01-26 00:46:57
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answer #6
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answered by Brad 1
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Issac Newton came up with that idea. If the two objects are not affected by atmospheric forces,then yes they will fall at the same rate. He also said what goes up,must come down. I guess he didn't foresee things like the Galileo explorer. Or those other exploring vessels we sent up, never to see again.
2007-01-26 00:51:58
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answer #7
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answered by dewhatulike 5
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Yes. all thing's drop at the same rate. it's pure physics
2007-01-26 01:07:12
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answer #8
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answered by metalman 3
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yes with out wind and air resistance the items will fall at the same rate.
2007-01-26 00:58:09
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answer #9
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answered by iknowus 1
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Yes, because this question does not relate with the size of the item, it's gravity, this proves that gravity levels at all place are the same, here let's test this, try using paper!
2007-01-26 00:48:28
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answer #10
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answered by skynet 3
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