pls. reply ASAP....
2007-01-25 23:54:52 · 5 answers · asked by Ninik 3 in Science & Mathematics ➔ Mathematics
You have to know at least one other measurement. The diagonals could be the same for a really long parallelogram.
2007-01-25 23:59:52 · answer #1 · answered by Rockstar 6 · 0⤊ 1⤋
Not enough information:
Let the sides be P and Q
Let the angle < 90° be A
Let the diagonals be D and d
Let the area be S
The area is
S=P*Q*sin(A)
You need 3 parameters
D=(P^2+Q^2+2*P*Q*cos(A))^(1/2)
d=(P^2+Q^2-2*P*Q*cos(A))^(1/2)
You have a system of only 2 equations
Or, without formulas:
Cross the 2 diagonals. Attach one to the other in their middle. Then rotate them. Any angle they form, they remain diagonals of a parallelogram but the area varies from 0 to a maximum of D*d/2 when the diagonals make an angle of 90°
You should know something more, the angle made by the sides, or the diagonals for instance
2007-01-26 08:24:04 · answer #2 · answered by Serban 2 · 1⤊ 0⤋
The answer would be the length (diagonal) times the breadth (diagonal. It doesn't matter if it's diagonal or not. You can cut off a trying from one side to fit the diagonal part on the other side, producing a rectangle with the same measurements provided! Cheers!
2007-01-26 07:58:59 · answer #3 · answered by MrYuQuan 3 · 0⤊ 0⤋
It can be anything between 0 and the half of the product of the diagonals, in the case of a rhombus.
2007-01-26 08:35:46 · answer #4 · answered by gianlino 7 · 0⤊ 0⤋
Not enough information.
2007-01-26 08:07:11 · answer #5 · answered by santmann2002 7 · 0⤊ 0⤋