I can't find pictures?

Question

of these anywhere can someone help with how to draw out the displayed formulae?

I've got

2 - bromo - 3 - methylhexane

and

2,2 - dimethyl - 4 - ethyloctane

i'm really stuck on this. Thanks

Answer 1

The first answer is correct (I think), but there was no explanation, so if you didn't understand it, the following might help:
2-bromo-3-methyl hexane
Draw your hexane molecule, i.e. 6 carbons in a row, and saturate with hydrogen atoms - two off each central carbon and 3 off the end two (the carbon chain can zig-zag a little). Take the second carbon along and rub out one of the hydrogens, then substitute a bromine atom (2-bromo).
Then go to the third carbon, rub out a hydrogen and substitute a CH3 (3 methyl).

2,2 dimethyl-4-ethyl octane:
Same sort of thing - draw 8 carbons with all the hydrogens. Substitute both hydrogens on the second carbon with CH3 (one up and one down (2,2 methyl). Take a hydrogen off the fourth carbon and substitute with a CH2-CH3 (ethyl) mini chain. This is the 4-ethyl.

Check that all carbon atoms have 4 bonds, there are no doubles. Hydrogens can only have one bond, so can never link anything - they just fill up any spare carbon bonds.

Good luck - I hope this made sense

Answer 2

2-bromo-3-methylhexane


CH3 - CH - CH - CH2 - CH2 - CH3
/ /
Br CH3

2,2-dimethyl-4-ethyloctane.
CH3
/
CH3 - C - CH2 - CH - CH2 - CH2 - CH2 -CH3
/ /
CH3 CH2-CH3

Hope this helps!!!

Answer 3

We can't draw in these answer boxes.

If you e-mail me I can e-mail you the drawn formulae & others you may want.

[e-mail]

Answer 4

H3CCHBrCH(CH3)CH2CH2CH3

H3CC(CH3)2CH2CH(CH2CH3)CH2CH2CH2CCH3