CDCl3 is a common solvent used for NMR analysis. It is used because most compounds will dissolve in it, it is volatile and therefore easy to get rid of, and it is non-reactive and will not exchange its deuterium with protons in the molecule being studied. It is also "silent" in the NMR and will not show peaks to interfere with the analysis of the compound of interest. However, whenever CDCl3 is used as an NMR solvent, a small singlet is always observed at 7.26 delta. What is this peak due to????
2007-01-25 18:12:30 · 3 answers · asked by Puri 2 in Science & Mathematics ➔ Chemistry
You can never get pure 100 % pure D compunds as is it is an isopote of H, if you read the labal of the bottle it will say some like 99.99% CDCl3 the other 0.01 % is CHCl3, and it is the hydrogen from CHCl3 that is the cause of the peak.
2007-01-25 18:23:53 · answer #1 · answered by Mr Hex Vision 7 · 1⤊ 0⤋
Nmr Solvent Peaks
2016-10-02 05:48:07 · answer #2 · answered by sardeep 4 · 0⤊ 0⤋
Cdcl3 Nmr
2016-12-08 17:44:42 · answer #3 · answered by pires 4 · 0⤊ 0⤋
The above answer is correct. Just like to add that the Deuterium is also used by the spectrometer as lock signal to add extra frequency stability to the spectrum. It is also used for 13C spectra where it is not "silent" it gives 3 peaks.
2007-01-25 23:55:23 · answer #4 · answered by deflagrated 4 · 0⤊ 0⤋
drutazo is right, the observed singlet in 1H-NMR is due to the residual CHCl3 present in the solvent.
Indeed, you'll always see an extra signal due to the residual non-deuterated fraction in any deuterated solvent you use (in each case at its own chemical shift and with its own multiplicity).
2007-01-26 00:18:49 · answer #5 · answered by Phoebe 1 · 0⤊ 0⤋