The perimeter of a rectangle is 48 m. the width of the rectangle is 2 more than 1/2 the length and the width.
2007-01-25 16:33:38 · 5 answers · asked by Magda A 1 in Education & Reference ➔ Higher Education (University +)
turn it into an equation:
48m = 2w + 2L
w=1/2(L+w) + 2
48m = 2[(1/2 L+w) +2] + 2L
48= L+W + 4 + 2L
48=3L +W +4
44=3L +W
2007-01-25 16:46:28 · answer #1 · answered by lee m 5 · 1⤊ 0⤋
Nikki and lee m are right.
48 / 4 = 12 + 2 = 14 (width)
14 + 14 = 28
48 - 28 = 20, so length should be 10 (20 / 2)
Because width is 0.5 (length + width) + 2;
you have 0.5 (10 + 14) + 2 = 14
12 + 2 =14 It checks
So in Nikki's equation:
44 = 3 L + W
44= 3 (10) +14
It checks too
2007-01-25 17:08:25 · answer #2 · answered by amrf-4 2 · 0⤊ 1⤋
What's the point of me just answering if you're just going to have to answer similar questions later? So let me try and help.
Divide the total amount of meters by two to get the length and width. Since it says you want half of the length and width, divide it in two again. Since it says you want two more than that number, simply add two to the number you have. There is the width.
For a quick check to make sure you're right, take the number you came up with, subtract two, and multiply it by 4. If you came up with any number other than 48 when you check your work, your mathematics was flawed somewhere along the way.
2007-01-25 16:47:30 · answer #3 · answered by Nikki 1 · 1⤊ 0⤋
48= 2 (1/2x + 2) + 2x
2007-01-25 16:37:27 · answer #4 · answered by thiiiis chick 3 · 0⤊ 1⤋
You have the basic formula...why do you need help??
2007-01-25 16:37:23 · answer #5 · answered by Lacey C 3 · 0⤊ 1⤋