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2007-01-25 16:31:01 · 7 answers · asked by Jackie G 1 in Science & Mathematics Mathematics

7 answers

Solve for "x" in 2x^2 - x - 1 = - 1

First: set the equation to "0" > add "1" to both sides...

2x^2 - x - 1 + 1 = - 1 + 1

2x^2 - x + 0 = 0

2x^2 - x = 0

Sec: factor the expression > find the greatest common factor...

x(2x - 1) = 0

Third: you have two x-variables to solve for > set both x-variables to "0"...

a. x = 0

b. 2x - 1 = 0
2x - 1 + 1 = 0 + 1
2x = 1

2x/2 = 1/2
x = 1/2

solutions: 0 and 1/2

2007-01-25 16:38:28 · answer #1 · answered by ♪♥Annie♥♪ 6 · 1 0

First add 1 to each side:

2x^2 - x = 0

Now factor x out

x(2x-1) = 0

so x = 0 or 2x - 1 = 0, which means x = 1/2

You have two solutions: x = 0 or 1/2

2007-01-25 16:39:01 · answer #2 · answered by Ken M 3 · 1 0

to exhibit powers, the convention without an prolonged personality set is to apply the '^' image, so a ability might want to coach as 2x^2 -x =a million. yet on to the challenge. that is component-able. 2x^2 -x =a million 2x^2 -x -a million =0 (2x+a million)*(x-a million)=0 first answer - 2x+a million=0 2x= -a million x = -a million/2 second answer - x-a million=0 x=a million

2016-12-03 01:44:04 · answer #3 · answered by lesure 4 · 0 0

2x^2-x-1=-1

Add -1 from both sides:
2x^2-x=0

Factor out an x:
x(2x-1)=0
x=0
2x-1=0
x=0 and 1/2

Check:
2(1/2)^2-1/2-1=-1
2(1/4)-1/2-1=-1
1/2-1/2-1=-1
-1=-1

2(0)^2-0-1=-1
-1=-1

I hope this helps!

2007-01-25 16:43:05 · answer #4 · answered by Anonymous · 0 0

2X2-X-1=-1
4X-X-1+1=0
3X=0
X=0/3
X=0

2007-01-25 17:34:07 · answer #5 · answered by Sarbjit 1 · 0 0

2x^2-x-1=-1
So,
2x^2-x=0
x(2x-1)=0
x=0 or x=0.5

2007-01-25 16:38:40 · answer #6 · answered by Keeper of Barad'dur 2 · 1 0

2X(2)-X-1=-1
2x(1)-x=-1
2x-x=-1
x=-1

2007-01-25 16:42:07 · answer #7 · answered by XFNET 2 · 0 2

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