Sin2x+Sin2x =2Sin2x.
2007-01-25 16:26:41
·
answer #1
·
answered by J.SWAMY I ఇ జ స్వామి 7
·
1⤊
0⤋
at first countless the poeple are incorrect in answeting this question. you're able to initiate by way of adjusting sin2x in terms of x basically (not 2x) hence sin2x = 2sinx*cosx somes in accessible. we've cosx = 2sinx*cosx --- yet YOU CANT DIVIDE the two factors by way of COSX (what if cosx = 0) so carry each thing over to the single area cosx - 2sinx*cosx = 0 cosx*(a million - 2sinx) = 0 cosx = 0 ------ a million-2sinx = 0 now resolve those 2 equatinos for the asnwer, even nonetheless there is not any given selection for x, and because cos and sin are infinite applications (bypass on constantly) there is not any a million answer so which you utilize the final formulation yet pondering the questino would not ask for the final recommendations this won't be the case and actually basically a poorly worded question. so fixing for 0<= x <= 360 cosx = 0 x = ninety, 270 tiers a million-2sinx = 0 2sinx = a million sinx = a million/2 x = 30 and a hundred and fifty tiers. giving very final recommendations as x = 30, ninety, a hundred and fifty and 270 tiers.
2016-12-12 20:29:49
·
answer #2
·
answered by ? 4
·
0⤊
0⤋
To be able to "solve" that it has to be equal to something, which I think you forgot to write down. Anyway, one of the trig identities is sin2x= 2sinxcosx, so that might help.
2007-01-25 16:29:43
·
answer #3
·
answered by Jen 2
·
0⤊
0⤋
Solve it in terms of what?
Since these are two of the same thing, we can make 2 of them.
2sin(2x)
Do you want it expressed in singular sines and cosines? Then the answer is, by the double angle identity,
2(2sin(x)cos(x)) = 4sin(x)cos(x)
2007-01-25 16:26:59
·
answer #4
·
answered by Puggy 7
·
1⤊
0⤋
u mean 2sin2x=0
sin2x=0
x=n(pie)/2 n is set of whole numbers
2007-01-25 16:26:26
·
answer #5
·
answered by ? 2
·
0⤊
0⤋
=2sin2x
2007-01-25 17:22:00
·
answer #6
·
answered by JAMES 4
·
0⤊
0⤋
2Sin2x
2007-01-25 16:28:07
·
answer #7
·
answered by siva k 2
·
0⤊
0⤋