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The parents are both heterozygous in all genes being BbHhEeRr. I'm having a difficult time with the genotype for this problem. Any help would be really awesome!!! I've already set up the Punnet Square, but I'm stuck! Thank you, thank you, thank you!!!

2007-01-25 15:42:25 · 2 answers · asked by Anonymous in Science & Mathematics Biology

2 answers

Good grief! That would be an enormous Punnett square!

I'd separate the cross into four monohybrid crosses and then multiply the phenotype ratios.
The four crosses will be:
Bb x Bb (which will yield 3 of the dominant phenotype: 1 rec.)
Hh x Hh ... 3:1 again
Ee x Ee
Rr x Rr

Let's say that B is black and b is white.
H is hairy and h is bald.
E is eyed and e is eyeless.
R is rough and r is smooth.

Take the four phenotype ratios:
3 black : 1 white
3 hairy : 1 bald
3 eyed : 1 eyeless
3 rough : 1 smooth

There are 256 boxes in this Punnett square (16 possible gametes from each parent), or we can look at the four phenotype ratios and see that each has four possibilities (4 x 4 x 4 x 4 = 256).

Look at the list of phenotype ratios and follow the path of a particular phenotype to find the probability. Multiply the numbers as you go.

Example:
Probability of black, bald, eyeless, smooth =
(3 x 1 x 1 x 1)/256 = 3/256

Probability of black, hairy, eyed, smooth =
(3 x 3 x 3 x 1)/256 = 27 / 256

2007-01-25 16:43:16 · answer #1 · answered by ecolink 7 · 1 0

dont use punent square, use product rule

2007-01-26 11:10:25 · answer #2 · answered by oumagicman 1 · 0 0

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