Help with algebra 2 Problem. Please show all work?

Question

Please show all steps and work i am very confused thx in advance.. heres the problem....person who shows good amt. of work and correct answer gets the pnts.

If the length and width of Rectangle A are 10 percent less and 30 percent less, respectively, than the length and width of Rectangle B, the area of A is what Percent smaller than the area of B. Thank you

Answer 1

Let the length and width of Rectangle B be L and w, respectively. It's area is then Lw.

The length of Rectangle A, then, will be .9L (10% less). The width will be .7w. The area of A, then, will be (.9L)(.7w) = .63Lw

That's 63% of the area of Rectangle B, so it's 37% smaller.

Answer 2

firstly, you should ask your teacher instead of asking random internet people to do your homework. but secondly, i hate math and would probably do the same thing, given your situation.

that said, let's assume that the length of rectangle B is 10 and the width is 20. 10% of 10 is 1; therefore the length of rectable A is 9. 30% of 20 is 6; therefore the width of rectangle A is 14. so the area of rect B is 200, and the area of rect A is 126. 126 is 63% of 200, so your answer is 63%.

edit: actually, your answer is 37%. i just can't read haha.

actually, you're probably suppose to write it in an equation, which isn't what i did, but i still arrived at the correct answer.

Answer 3

Rectangle 1:

Length- 100 cm
Width- 50 cm

Rectangle 2:

Length- 90 cm(10% less than 100)
Width- 35 cm (30% less than 50)

Rectangle 1 area: 5,000 cm
Rectangle 2 area: 3150 cm

3,150 divided by 5000 = 0.63, so rectangle b is 37% smaller than A

Answer 4

La = (Lb -.1Lb) : Wa = (Wb - .3Wb)

La =.9Lb : Wa = .7Wb

(.9Lb)(.7Wb)

(.9*.7)(Lb*Wb)

Do these steps make sense?
Figure out the last bit on your own.