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9 answers

Bears are wearing white
colts are wearintg blue

2007-01-25 15:21:36 · answer #1 · answered by Salamander 1 · 0 0

I think it is decided by seeding and regular season record. Bears should be wearing their home uniforms (aka blue) while the Colts will be wearing their away uniforms (aka white). I do believe the Bears DO have the choice though. If they want to wear their away jerseys for whatever reason, they can decide this because of their higher seed. Apparently the reason for the home team wearing a dark color is a psychological thing? (see source) I don't quite believe it, but that's just been the norm. So if all work out right:

Bears in blue.

Colts in white.

2007-01-26 03:54:18 · answer #2 · answered by lissamajoo 1 · 0 0

Lame! Anyway, prolly the Bears in Blue Colts in all white.

2007-01-26 01:48:13 · answer #3 · answered by Simiman77 2 · 0 0

Colts are the away team, they are making the coin-toss call, therefore they will be wearing their blue, while Chicago will wear the home white colored uniforms

2007-01-26 08:24:16 · answer #4 · answered by DJ Mach Z-Ro 3 · 0 0

Colts in white ,Bears in blue

2007-01-25 23:16:48 · answer #5 · answered by Anonymous · 0 0

the "home" team rotates every other year between the afc and nfc. it has nothing to do with recors or seeds. last year the steelers were the home team and chose to wear white. this year the bears are the home team and have the option to wear whichever uniforms they choose, even though they have yet to announce it.

2007-01-26 04:22:48 · answer #6 · answered by mitchell_8_5 3 · 0 0

Colts in white and BEars in Blue....the bears are too cheap so they only have one color for their uniform....haha....the colts are BIG BLUE and will dominate...for the SB

2007-01-25 23:42:36 · answer #7 · answered by football junkie 3 · 2 1

that would be cool if the bears wore their orange jerseys

2007-01-26 03:43:52 · answer #8 · answered by Anonymous · 0 0

Bears have choice but have not decided yet.

2007-01-25 23:35:48 · answer #9 · answered by Anonymous · 0 0

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