Physics car problem (may be simple?)?

Question

A car traveling at 95 km/h strikes a tree. The front end of the car collapses and the driver comes to rest after traveling .80 m. What was the average acceleration of the driver during the collision? Express the answer in terms of "g's", where 1.00 g = 9.80 m/s^2.

I know the answer is -440 m/s or 44 g's.

help would be appreciated... i got all my other problems but this one. It baffels me.

Answer 1

For this, use Torricelli's equation to determine the accelleration without time:
Vf^2 = Vi^2 - 2ad
where Vf = 0, Vi = 95 km/h, and d = .80m.

Step 1: Convert Vi to m/s
95 km/h * (1000 m * 1 h / 1 km * 3600 sec) = 26.3889 m/s

Step 2: Use Torricelli's eqn:
Vf^2 = Vi^2 - 2ad
0 = (26.3889 m/s)^2 - 2a * .8
0 = 696.373 - 1.6a
1.6a = 696.373
a = 440 m/s (solution)

Answer 2

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