Math:Order Of Operations equations?

Question

4[30-(10-2)*3]=?? ; 5+[30-(6-1)^2]=?? ; 2[12+(5-2)^2]=?? ; [8*2-(3+9)]+[8-2*3]=??

I have got the answer I just need to know if mine are right.

Answer 1

Use PEMDAS...( ), exponents, multiplication, division, addition and subtraction.

1. 4[30 - (10 - 2)*3]

4[30 - (8*3)]
4[30 - 24]
4[6]
= 24

2. 5 + [30 - (6 - 1)^2]=

5 + [30 - (5)^2]
5 + [30 - (5)(5)]
5 + [30 - 25]
5 + 5
= 10

3. 2[12 + (5 - 2)^2]

2[12 + (3)^2]
2[12 + (3)(3)]
2[12 + 9]
2[21]
= 42

4. [8*2 - (3 + 9)] + [8 - 2*3]

[8*2 - (12)] + [8 - 6]
[16 - (12)] + [8 - 6]
[4] + [8 - 6]
[4] + [2]
4 + 2
= 6

Answer 2

1.) 4[ 30 - (10 - 2) * 3]
4[ 30 - 8 * 3 ]
4[ 30 - 24]
4[6]
24

2.) 5 + [30 - (6-1)^2]
5 + [30 - 5^2]
5 + [30 - 25]
5 + 5
10

3.) 2[12 + (5 -2)^2]
2[ 12 + 3^2]
2[12 + 9]
2[21]
42

4.) [8 * 2 - ( 3 + 9 )] + [ 8 - 2 * 3]
[ 8 * 2 - 12] + [8 -6]
[16 - 12] + 2
4 + 2
6

Answer 3

The only step that needs to be added to the order is that if there are several + or - operations in a row, they are to be done left to right.
(6-4+3-2)
6-4 = 2
2+3 =5
5-2 = 3
Same with X and /.

Answer 4

First, you do the operations inside parenthesis or brackets. Then the order is exponents, mutiply, divide, add, subtract.

The examples you show all have parentheses and brackets to show the order, except the last one.

[8*2-(3+9)]+[8-2*3] = [8*2-(3+9)]+[8-{2*3}]
... = [16 - (12)] + [8 - {6}]
... = [4] + [2]
... = 6

Answer 5

Aleways work these problems from the inside out. For example, on the first problem follow these steps: 1) 10-2. 2) Take that answer multiply by 3. 3) Subtract that number from 30. 4) Multiply that answer by 4.

Work the others in the same manner. Hope this was helpful!

Answer 6

Instead of listing all of your problems, why don't you ask for the method behind the order of operations?

() is done first
[] is next
{} is after []

* and / are done before + and -

So for example, on the first one, 4[30-(10-2)*3]=??

You'll do 10-2 first and get 8
you'll multiply 8 by 3 next to get 24
then you do 30 - 24 to get 6
then multiply 4 by 6 to get 24.

You do the other ones.

Answer 7

Simplify here: 7/8 (one million+one million/4)/(one million/4)^2 7/8 (one million+one million/4)/(one million/4)^2 = (7 (one million+one million/4))/(8 (one million/4)^2): (7 (one million+one million/4))/(8 (one million/4)^2) (one million/4)^2 = one million^2/4^2: (7 (one million+one million/4))/(8×one million^2/4^2) one million^2 = one million: (7 (one million+one million/4))/(8 one million/4^2) 4^2 = sixteen: (7 (one million+one million/4))/(8/sixteen) placed one million+one million/4 over the ordinary denominator 4. one million+one million/4 = 4/4+one million/4: (7 4/4+one million/4)/(8/sixteen) 4/4+one million/4 = (4+one million)/4: (7 (4+one million)/4)/(8/sixteen) 4+one million = 5: (7×5/4)/(8/sixteen) The gcd of 8 and sixteen is 8, so 8/sixteen = (8×one million)/(8×2) = 8/8×one million/2 = one million/2: (7×5/4)/(one million/2) 7×5/4 = (7×5)/4: (7×5)/4/(one million/2) Multiply the numerator by skill of the reciprocal of the denominator, ((7×5)/4)/(one million/2) = (7×5)/4×2/one million: (7×5×2)/4 2/4 = 2/(2×2) = one million/2: (7×5)/2 7×5 = 35: answer: | | 35/2

Answer 8

ANSWER IT OR NOT

94, 0, 103, 6

ASK UR PARENTS