pre calculus solving right triangles!?

Question

directions: solve the right triangle.

not the best picture but hey at least it a picture.
here the URL.
http://i15.photobucket.com/albums/a372/riannabanana/rt.jpg

okay i need help. i understand how to find the other degree, which is 45 degrees. i understand that it is a 45 45 90 triangle. i need help on telling what kind of ratio it is? like sin cos csc cot... etc. you know. i dont undertsand how to determine this and where to go on from there. please help!

Answer 1

I assume you have to find the other two sides and the third angle (which you got).

You know the angle and the side opposite it and you know it's a right triangle.. To get the hypotenuse and the adjacent angle, use the TAN and SIN relations.

tan < = opp/adj (tan 45 = 16/adj)
sin < = opp/hyp (sin 45 = 16/hyp)

Answer 2

Sin = opp / hyp
Cosine = adj / hyp
Tangent = opp / adj

So for your picture you have:

sin of 45° = 16/hyp
look up the sin value in your table and then solve

Answer 3

There are a couple of things that you have to memorize. (Sorry, but there is no way around it):

Sin = opp / hyp
Cosine = adj / hyp
Tangent = opp / adj

So for your picture you have:

sin of 45° = 16/hyp
look up the sin value in your table and then solve

Answer 4

sin = opposite/hypotenuse
cos = adjacent/hypotenuse
tan = sin/cos = opposite/adjacent
sec = 1/cos = hypotenuse/adjacent
csc = 1/sin = hypotenuse/opposite
cot = 1/tan = cos/sin = adjacent/opposite