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what is the radius of an automobile tire that turns with a frequency of 11Hz and has a linear speed of 20.0 m/s?

2007-01-25 13:00:57 · 3 answers · asked by globesk8er999 1 in Science & Mathematics ➔ Physics

The circumference is 20/11 m

The radius is
related to circumference as 2*pi*r=C
10/(11*pi)=r

j

2007-01-25 13:09:05 · answer #1 · answered by odu83 7 · 0⤊ 0⤋

T = 1/f = 1/11hz = .0909s
In one rotation:
dist = rate * time ------ circumference is 2piR
2piR = 20 m/s * .0909s
2piR = 1.818m/s/s
R = .289m

2007-01-25 13:14:03 · answer #2 · answered by The Q-mann 3 · 0⤊ 0⤋

V=(2*pi*r)/T

find T first.

1s/11rel= .09s

20m/s= (2*pi*r) / .09
1.81m=2*pi*r
r= 1.81/(2*pi)
r=0.29m

2007-01-25 13:11:29 · answer #3 · answered by 7 · 0⤊ 0⤋