where do these lines intersect?

Question

The first line is y=6221X-81132
the second is y=60000x-81132

if you cant find that then try this one:
first line is 850000=6221x-81132
second line is 850000=60000x-81132

Answer 1

y=6221x-81132
y=60000x-81132

6221x-81132=60000x-81132
6221x=60000x

The only value that makes this statement true is x=0
Plug 0 into x and you get -81132 for y in both equations
so...
(0,-81132) is your answer

Answer 2

Point of intersection is (0,-81132)

Point of intersection is (0. 850000)

Answer 3

The line intersect at y=-81132 and x=0.

Answer 4

So, for the two strains to be perpendicular, they should have slopes that are the destructive reciprocal of another, and each ought to have a slope equivalent to the spinoff of x^2 on the factor of intersection. to boot, the two strains you're searching for ought to intersect at x = 0 (which defines the y-axis). The equation for a line tangent to y = x^2 at a factor x1 is y1 = 2x1*x - x1^2. the fee of this at x = 0 is -x1^2. for this reason, our different tangent line (y2) ought to have a y-intercept of -x1^2 to boot. the only different cost of x2 pleasing -x2^2 = -x1^2 is x2 = -x1. for this reason, the 2d tangent line ought to have a slope of -2x1, and so the equation for the 2d tangent line is y2 = -2x1*x - x1^2. be conscious that there are an infinite style of suggestions, because of the fact that any arbitrary x1 will do.

Answer 5

my scientific calculator says (0, -81132)

Answer 6

(0,-81132)