Let x be the length of the side of a square
Then the area will be x^2
If the side is tripled, then the area is (3x)^2 = 9x^2
So the area is 9 times as much
2007-01-25 12:38:51
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answer #1
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answered by kellenraid 6
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When one length of a regular square is tripled, all of the other three sides will triple, too.
We all know that to find the area, you multiply to sides that are connected at one right angle.
If square length 1 (sql1) triples, square length 2 (sql2) will triple.
Since these two lines are at the same right angle of the square, you can multiply these for the area.
((sql1) x 3) x ((sql2) x 3) = A
If the square lengths were both 2 inches, we can plug it into the equation like so:
((2 in) x 3) x ((2 in) x 3) = A
(6 in) x (6 in) = A
36 inches squared = Area or
A = 36 in^2
The area will be nine times larger because...
(3L) x (3L) = A
3L represents the Length tripled (x3)
and the A (area) is 9.
2007-01-25 20:56:00
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answer #2
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answered by T.VO 3
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The area will be multiplied by 3^2 =9
2007-01-25 20:38:45
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answer #3
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answered by santmann2002 7
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The area will be 9X larger -- a 2x2 square has an area of 4 square units. triple the sides, we get 6x6, which is 36 square units, which is also 9x 4. This works for any size square....
2007-01-25 20:38:37
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answer #4
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answered by Deasel98 5
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Easy. The area is 9 times the original area because is x is the original side, x times x is x squared and 3x times 3x is 9x squared
2007-01-25 20:36:55
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answer #5
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answered by darthfroehlious 2
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The area gets nine times larger
2007-01-25 20:38:42
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answer #6
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answered by xjgege 2
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A=s^2
let t=3s
A=t^2=(3s)^2=9s^2 so the area is 9 times as large.
2007-01-25 20:40:01
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answer #7
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answered by yupchagee 7
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The area will be nine times larger.
2007-01-25 20:36:01
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answer #8
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answered by John T 6
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