.60y=.20y+100
.40y=100
y= 250
2007-01-25 12:34:15
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answer #1
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answered by 7
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.60y= .20y + 100
-.20y=-.20
.40y= 100
divide .40y by .40 and then divide 100 bye .40
y= 250 im positive
2007-01-25 20:37:43
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answer #2
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answered by Anonymous
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250
2007-01-25 20:32:45
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answer #3
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answered by Anonymous
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.60y=.20y-20y+100
.60y-.20y=100
.40y=100
.40y x100=100x100
40y=10000
y=250
2007-01-25 20:34:55
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answer #4
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answered by Dave aka Spider Monkey 7
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0.60Y=0.20Y + 100
0.60Y - 0.20Y = 100
0.40Y=100
Y=100/0.40
Y= 250
2007-01-25 20:37:07
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answer #5
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answered by cute_gurl 1
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Solve for "y" > 0.60y = 0.20y + 100
First: combine "like" terms > subtract "0.20y" from both sides...
0.60y - 0.20y = 0.20y - 0.20y + 100
0.40y = 100
Sec: isolate "y" on one side > divide both terms by "0.40" >
0.40y/0.40 = 100/0.40
y = 250
2007-01-25 20:36:11
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answer #6
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answered by ♪♥Annie♥♪ 6
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.60y = 0.6y
so, don't for get o.xxx infont 'dot'
0.4y = 100
y = 250......ans.....
2007-01-25 20:34:53
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answer #7
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answered by Sir Jas 2
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subtract y from both sides
.40y = 100
divide by .40
and you get (100/.4) = y
2007-01-25 20:32:35
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answer #8
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answered by sur2124 4
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