find the magnitude of the acceleration of the electron using the information below?

Question

An electron is released from rest in a uniform electric field of magnitude 2.20 104 N/C. Calculate the magnitude of the acceleration of the electron. (Ignore gravitation.)

Answer 1

The definition of electric field gives:
F = q0 x E, where q0 = 1.6x10−19, elementar charge.
Additionaly, Newton's second law gives F = ma (m = mass of an electron = 9.1 x 10−31 kg).
So:
a = q0 x E / m = 3.87x10^15 m/s2

Answer 2

a=Eq/m
and the rest of the part is done by ur calculator

whenver a charge is place ina field(electric) it experiences a force of Eq and gets accelerated with a force equals ma .. law of conservation of energy