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??? show the steps of what you did please

2007-01-25 11:30:04 · 6 answers · asked by NoNome 2 in Science & Mathematics Mathematics

6 answers

first, you multiply the real numbers

when multiplying common variables, you add the exponents

collect the like terms that are being multiplied:
= (5*12) x^3 x^1 y^2 y^7 z^11 z^-4
= 60 x^(3+1) y^(2+7) z^(11-4)
= 60 x^4 y^9 z^7

2007-01-25 11:37:17 · answer #1 · answered by Anonymous · 0 0

exchange the mixed fraction 5¼ into an unsuitable fraction 5 (4/4) + ¼ = 21/4 then do the multiplication (21/4)(11/12) = (21 * 11) / (4 * 12) = 231 / 40 8 = 4 39/40 8 [4 and thirty-9 40-eighths)

2016-12-12 20:20:10 · answer #2 · answered by lot 4 · 0 0

5 x 12 = 60
X^3 x X^1 = X^(3+1) = X^4
Y^2 x Y^7 = Y^(2+7) = Y^9
Z^11 x Z^-4 = Z^(11-4) = Z^7

Answer = 60X^4Y^9Z^7

2007-01-25 11:46:52 · answer #3 · answered by Rocky 1 · 0 0

(5x^3y^2z^11)(12xy^7z^-4)

(5 * 12) * x^(3 + 1) * y^(2 + 7) * z^(11 + (-4))
60x^4y^9z^(11 - 4)
60x^4y^9z^7

ANS : 60x^4y^9z^7

2007-01-25 12:00:29 · answer #4 · answered by Sherman81 6 · 0 0

(5x^3y^2z^11)
3*3*3=9
(5x9^2^11)
5x9=45
45^2^11
45*45=90
(45x90^11)
45x90=4050
(4050^11)
4050x11=445550x12^7^4
445550x12=534600
534600^7=3742200x4=14968800

Answer= 14,968,800

2007-01-25 11:49:17 · answer #5 · answered by Anonymous · 0 0

?????? ur kidding me right?

2007-01-25 11:35:50 · answer #6 · answered by natalie_rivera03 2 · 0 0

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