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A 7 kg block being pulled across a table by a horizontal force of 40 N also experiences a frictional force of 10 N. What is the acceleration of the block? m/s2

2007-01-25 11:12:02 · 2 answers · asked by bibun 2 in Science & Mathematics ➔ Physics

2 answers

Newton's second law: F = ma
F = 40 N − 10 N = 30 N
a = F/m = 4.3 m/s2

2007-01-25 11:17:10 · answer #1 · answered by Dorian36 4 · 0⤊ 0⤋

F = ma
40 - 10 = 7a
30 = 7a

a = (30/7) m/s^2

2007-01-25 19:16:55 · answer #2 · answered by sur2124 4 · 0⤊ 0⤋