find the lcm of the monomials.
5a, a^2
22k^4, 34k^2
2007-01-25 10:43:00 · 4 answers · asked by Mike 2 in Science & Mathematics ➔ Mathematics
5a, a^2
5a^2
22k^4, 34k^2
2*11*17*k^4=374k^4
2007-01-25 11:40:37 · answer #1 · answered by yupchagee 7 · 14⤊ 0⤋
1) The highest exponential term is a^2, so there has to at least be an a^2 in the LCM. There's a 5 in the other term and no other numbers in either, so there has to be a 5 in the LCM. So the answer is 5a^2. It's a multiple of both.
2) The highest exponent is k^4, so that has to be in our LCM. Now look at 22 and 34. The prime factors of 22 are (2, 11) so we need to find the smallest multiple of 34 that has these. 34 is already divisible by 2 but not 11, so the smallest is going to be 34*11 = 374. Therefore the LCM is 374k^4.
2007-01-25 19:09:23 · answer #2 · answered by Anonymous · 0⤊ 0⤋
1) 5a^2
2) 2*11*17k^4 = 374 k^4 ( You should find the lcm of 22 and 34 which is just 2*11*17
2007-01-25 20:37:06 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋
5a^2
2*11*17 k^4
2007-01-25 18:49:36 · answer #4 · answered by Professor Maddie 4 · 1⤊ 0⤋