2007-01-25 10:20:35 · 11 answers · asked by sire fartness(i'm a girl) 1 in Entertainment & Music ➔ Celebrities
i personally think see does but if she likes how she is then fine....
2007-01-25 10:37:04 · answer #1 · answered by Anonymous · 0⤊ 0⤋
I haven't seen her recently...but judging by pictures I sw a couple of months ago she didn't seem unhealthy although it's clear she's lost quite a lot of weight in the past year or so...and at times she does look a little underweight so I suppose putting on a few pounds couldn't hurt. As long as she isn't suffering with any eating disorder and she's healthy then I don't think it's really an issue.
2007-01-25 18:27:30 · answer #2 · answered by Selz 3 · 1⤊ 0⤋
i do b/c she looked so awesome in her last episodes of Lizzie(or wuteva it was) but now it's like she i just empty. wheneva i look at her all i see is a sack of bones that thinks she doesn't fit in with hollywood unless she is as skinny as her pinky finger
2007-01-25 22:26:28 · answer #3 · answered by [*]Heart Melter[*] 2 · 0⤊ 0⤋
It seems like all celebs need to gain weight these days..... why can;t they see they look fantastic already???
2007-01-25 18:26:06 · answer #4 · answered by Anonymous · 3⤊ 0⤋
If she wants to go around looking like that then thats not my problem.
2007-01-25 18:35:53 · answer #5 · answered by BellaMars 4 · 0⤊ 0⤋
She definitely needs to.
2007-01-25 19:32:01 · answer #6 · answered by face_downxx 3 · 0⤊ 0⤋
Hillary duff is a fake whore...why do go give a flying fuuck ?
2007-01-25 18:36:38 · answer #7 · answered by Anonymous · 0⤊ 4⤋
no. she finally lost all of her baby fat. and now she looks great. so what? a celebrity needs to be obese to be healthy? (:/
2007-01-25 18:44:04 · answer #8 · answered by Anonymous · 0⤊ 0⤋
now...yes, she used to look better, more unique, know she just looks like the rest of "them"
2007-01-25 18:46:17 · answer #9 · answered by Heather 3 · 0⤊ 0⤋
I think she needs to gain about 215lbs, which happens to be my wieght!
2007-01-25 18:37:35 · answer #10 · answered by ralfinader 3 · 0⤊ 2⤋