i like these two really nice bikini's they are the same .one is yellow and one is blue. i have blondish red hair and blue hair and a bit of a tan ,which colour will look nicer on me?thanx
2007-01-25 09:49:50 · 10 answers · asked by natashas 2 in Beauty & Style ➔ Fashion & Accessories
Blue...it will bring out your eyes. Yellow is a hard color to pull off.
2007-01-25 09:59:35 · answer #1 · answered by Sara 4 · 0⤊ 1⤋
blue it brings out the tan more to look nicer and the yellow may clash with the blonde and red in your hair
2007-01-28 19:16:50 · answer #2 · answered by mara 2 · 0⤊ 0⤋
The yellow will look better if you have a really deep tan. If not, the blue would work.
2007-01-26 11:24:07 · answer #3 · answered by nudie chick 6 · 0⤊ 0⤋
Did you mean blue eyes? I think so. I say yellow. I think blue works better on dark haired women.If maybe you could post pictures of you IN said bikinis, I could answer definitively.......just kidding, I know, I'm a pig...darn testosterone!
2007-01-25 18:05:02 · answer #4 · answered by Anonymous · 0⤊ 0⤋
they both will look nice. if you have a tan id say the yellow would look better.. but if your tan is not that great go for the blue you dont want your skin to be too close to the yellow color..
2007-01-25 17:59:38 · answer #5 · answered by hallie 5 · 0⤊ 1⤋
Blue hair? You mean you've dyed it to match the bikini? :-)
Well, if it had been blue eyes, I'd have said wear the yellow one to match your coloring, but iwth blue hair ................. :-)
2007-01-25 18:24:47 · answer #6 · answered by Feinschmecker 6 · 0⤊ 0⤋
BLUE! light is always for dark color hair. light color hair is for colors like blue and pinks and so on!
2007-01-25 18:02:55 · answer #7 · answered by cheer_4_life 2 · 0⤊ 0⤋
go with the blue. what type of bikini is it?
2007-01-27 08:58:58 · answer #8 · answered by camorningsurfer 4 · 0⤊ 0⤋
the blue one is better
2007-01-25 17:59:48 · answer #9 · answered by Rakiya C 2 · 0⤊ 0⤋
blue =]
yellow can make you look pale sometimes
2007-01-25 18:10:45 · answer #10 · answered by Anonymous · 0⤊ 0⤋