evaluate h(-2/3) if h(x) = [x-2]?

2 ⤊

evaluate h(-2/3) if h(x) = [x-2]?

2007-01-25 08:15:58 · 3 answers · asked by lana l 1 in Science & Mathematics ➔ Mathematics

3 answers

I'm assuming the brackets stand for the greatest integer function.
h(-2/3) = [-2/3 - 2]
= [ -2/3 - 6/3]
= [-8/3]
= [-2.66666...]
Now what is the greatest integer that is less than or equal to
-2.66666....?
= -3

2007-01-25 08:20:08 · answer #1 · answered by MsMath 7 · 2⤊ 0⤋

This simply means to plug in (-2/3) in place of x

h(-2/3) = [ (-2/3) - 2 ] = -8/3

2007-01-25 16:21:15 · answer #2 · answered by Nes 3 · 0⤊ 0⤋

-3

You get this because you have to subtract two and then use the greastest integer function which means the answer is the integer lower or equal to the #

2007-01-25 16:22:16 · answer #3 · answered by noaster 2 · 0⤊ 0⤋