2007-01-25 08:12:46 · 7 answers · asked by avemaria 2 in Science & Mathematics ➔ Mathematics
x^2 - 8x + 7 = 0
(x-7)(x-1) = 0
x - 7 = 0 or x - 1 = 0
x = 7 or x = 1
If a number n, is a zero of the function, then f(n) = 0.
If you are given a list of numbers, and you need to find the zero, you can just plug each number in for x and see which one results in zero.
For example,
f(1) = 1^2 - 8(1) + 7
f(1) = 1 - 8 + 7
f(1) = 0
SInce f(1) = 0, then 1 is called a zero of the function.
2007-01-25 08:16:48 · answer #1 · answered by MsMath 7 · 3⤊ 0⤋
7
2007-01-25 08:18:19 · answer #2 · answered by th3_ch0s3n_0n3 2 · 0⤊ 0⤋
The y-intercept is what y is while x is 0: 0^2 - 8(0) + 7 = 7. that must be (0,7). you do no longer ought to apply derivatives to discover the vertex in Algebra. you could rapidly discover the x-coordinate of the vertex of a parabola by skill of utilising the -B/2A factor of the quadratic equation. hence A = one million, B = -8, C = 7 so -B/2A = -(-8)/2(one million) = 4. while x = 4, y = 4^2 - 8(4) + 7 = sixteen - 32 + 7 = -9. So the vertex is (4, -9).
2016-11-27 01:43:52 · answer #3 · answered by Anonymous · 0⤊ 0⤋
f(x) = x² - 8x + 7
to find the zeroes
0 = x² - 8x + 7
0 = (x-7) (x-1)
x-7 = 0 OR x-1 = 0
x = 7 OR x=1
Or we say 1 and 7 are zeroes of f(x)
2007-01-25 08:17:57 · answer #4 · answered by bequalming 5 · 0⤊ 0⤋
23
2007-01-25 08:19:43 · answer #5 · answered by Brite Tiger 6 · 0⤊ 0⤋
(x-1)(x-7)
x=1 x=7
2007-01-25 08:17:51 · answer #6 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
I agreed with MsMath Answer
2007-01-25 08:18:49 · answer #7 · answered by farooqamlani 2 · 0⤊ 0⤋