write an equation in slope-intercept form for the line that passes through (3,5) and (-2,1)?

Question

please help?

Answer 1

exquation for a line is y=mx+b

m (slope) = (y2-y1)/(x2-x1) = (5-1)/(3+2)=4/5

the intercept can be found from substitution

5=4/5*3+b ==> 25/5=12/5+b ==> b=13/5

check with answer with other set of pts.

1=4/5*(-2)+13/5 = (-8)/5+13/5 = 5/5 = 1

Answer 2

first find slope
subract y1 - y2 --> 5-1=4
subtract x1 - x2 --> 3- (-2) = 5
slope is 4/5 or decimal form 0.8

then use equation y=mx+b
plug in 4/5 for m
then using either points (3,5) or (-2,1) put that in for x and y

i'll use (3,5)
y=mx+b
5 = (4/5) (3) + b
5 = 2.4 + b
5 - 2.4 = b
b= 2.6 which is also 13/5

using (-2,1)
y=mx+b
1 = (4/5) (-2) + b
1 = -1.6 + b
1 - (-1.6) = b
1 + 1.6 = b
b= 2.6 which is also 13/5

thus equation for this problem is
y = 4/5x + 13/5
or
y = 0.8x + 2.6

Answer 3

very simple
find teh slope by (y2-y1)/(x2-x1)
then use point slope form: y-y1=m(x-x1)
put in any point for (x1,y1) and the slope for m and solve the equation
cant do it off the top of my head, but I hope I helped do your homework for you?

Answer 4

y=mx+b
m=5-1/3--2
m=4/5
y=4/5x+b
5=4/5(3)+b
2.6=b
y=4/5x+2.6

i
think at least