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carry out the following divisions and hence write the results in the form DIVIDEND=DIVISOR X QUOTIENT + REMAINDER

a) (3x^3 - 9x^2 - 5x + 4)/(x+3)

2007-01-25 07:37:41 · 3 answers · asked by Exitz Woundz 1 in Science & Mathematics Mathematics

3 answers

9x³ - 9x² - 5x + 4 / x + 3

3x² - 18x + 49 remainder of - 143

- - - - - - - -s-

2007-01-25 08:25:41 · answer #1 · answered by SAMUEL D 7 · 0 0

P(x)=D(X)*Q(X)+R(X)

3x^3-9x^2-5x+4 = (x+3)(3x^2-18x+49)-143

2007-01-25 15:56:33 · answer #2 · answered by aznskillz 2 · 0 0

3x³ -9x² - 5x + 4 = (x+3) * (3x² - 18x + 49) + 143/(x+3)

2007-01-25 15:54:05 · answer #3 · answered by bequalming 5 · 0 0

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