There are 3 piles of poker chips. If you take 5 off of the first 2 piles and then put them on the 3rd pile, the 3rd pile will have as much as the first 2 combined. The answer is 20. How would you put this into a formula?
2007-01-25 06:38:40 · 6 answers · asked by Obi-wan Kenobi 4 in Science & Mathematics ➔ Mathematics
bequal...thank you so much. It was driving me crazy. Sorry everyone if you didn't understand. 20 chips is how much each pile started with. I knew the answer I just didn't know how to set it up.
2007-01-25 07:28:58 · update #1
first pile has x chips
second pile has y chips
Third pile has z chips
(x-5) + (y-5) = z + 10
Oh I see.. x, y and z are all equal
(x-5) + (x-5) = x+10
2x-10=x+10
x=20
2007-01-25 06:46:11 · answer #1 · answered by bequalming 5 · 1⤊ 0⤋
The answer is 20. what's the question?
let x,y,z be number of chip in the 3 piles
so (x-5)+(y-5)=z+5+5 - the only formula you can have here
or piles are equal at the beginning?
2007-01-25 14:45:06 · answer #2 · answered by Anonymous · 1⤊ 0⤋
Let statement
1st pile=x(10)
2nd pile=x(10)
3rd pile=x+10(20)
Equation
2x = x+10
2x-x=x-x+10
x=10
Check
x+x=x+10
(10)+(10)=(10)=10
20=20
Sentence: Therefore there are 20 poker chips in the third pile.
2007-01-25 14:52:07 · answer #3 · answered by Anonymous · 0⤊ 0⤋
To start lets say:
The first pile has x number of chips in it.
The second pile has y number of chips in it.
The third pile has z number of chips in it.
Therefore,
you subtract 5 chips from the first pile (x-5),
you subtract 5 chips from the second pile (y-5),
and you add 10 chips to the third pile (z + 10)
We also know that the third pile is equal to the combination of the first two piles.
SO,
x-5 + y-5 = z + 10,
x + y - 10 = z + 10,
x + y = z + 20
Now we sort of have our answer.
If we assume that the piles have an equal number of chips to begin with then we get
x=y=z or
y=x and z = x
now we can substitute y and z and we get
x + x = x +20
subtract x from both sides and we get
x = 20
2007-01-25 14:59:16 · answer #4 · answered by Mark T 1 · 1⤊ 0⤋
No guarantees on this one, because I haven't done this stuff in years ... ages ... decades ... eons, but it seems to me that if pile 1 is called P and pile 2 is called Q and pile 3 is called R, then
(P-5) + (Q-5) = 20 - R
Hopefully, someone who knows what they are doing will answer this one.
2007-01-25 14:44:53 · answer #5 · answered by istitch2 6 · 1⤊ 0⤋
Can't do it, the answer to what is 20?
2007-01-25 14:45:40 · answer #6 · answered by partout250 4 · 1⤊ 0⤋