Northwest airlines gives out peanuts to all passengers who want them. On severalrevent flights to boston, 72% of the passengers who were asked avvepted the peanuts, and 23% rejected the peanuts. A total of thirty-six passengers were asleep and were not asked. How many passengers were on these flights??
2007-01-25 06:18:15 · 10 answers · asked by steffyjo5598 1 in Science & Mathematics ➔ Mathematics
72%+23%=95% either accepted or rejected the peanuts. That leaves 5% who were asleep. 36 passengers were asleep so 36=5% of the total
total=36/.05=720 passengers
2007-01-25 06:24:46 · answer #1 · answered by yupchagee 7 · 14⤊ 1⤋
If I understand this problem, the thirty six sleeping passengers account for 100-72-23=5 percent of the total number of passengers. Therefore, if x is the total number of passengers, .05*x=36....x=720.
2007-01-25 06:29:15 · answer #2 · answered by bruinfan 7 · 0⤊ 0⤋
.72x + .23x + 36 = x
x = 720
This should be the answer, however it is worded poorly. Your question says "72% of the passengers who were asked" not "72% of the total passengers". This implies that 72% of the people asked (were awake) wanted peanuts not 72% of the entire population. This means that 5% of the people awake neither accepted nor rejected the peanuts and are unaccountable for. If this is infact the case then 720 is not the answer and we need more information.
2007-01-25 06:29:03 · answer #3 · answered by E 5 · 0⤊ 0⤋
72% accepted
23% rejected
Total 95% (72+23) were offered
Remaining 5% (100-5) were asleep.
If 5% is 36 passengers (as mentioned in the problem) how many is 100%
(100/5) * 36 = 20*36 = 720
So the total number of passengers in the flight were 720
Thanks,
2007-01-25 06:28:07 · answer #4 · answered by ahsanmohd 2 · 0⤊ 1⤋
Assuming the flight attendants asked everyone who was awake, the number who accepted or rejected the peanuts doesn't matter, just how many total. 72% + 23% = 95%, leaving 5%, or 1/20th, that weren't asked. 36 * 20 = 720, so 720 passengers were on the flights, total.
2007-01-25 06:27:06 · answer #5 · answered by gamblin man 6 · 0⤊ 1⤋
P = passengers. .72P = accepted and .23P = rejected
.05P = 36 who were asleep and not asked
P = 36 ÷ .05 = 36 X 20 = 720 total passengers
.72P = .72 X 720 = 518 accepted
.23P = .23 X 720 = 166 rejected
.05P = .05 X 720 = 36 not asked
Total passengers = 720
2007-01-25 06:47:11 · answer #6 · answered by Marv 2 · 0⤊ 0⤋
Read the question carefully--
95% of the passengers...that were awake and asked... accepted or rejected the peanuts. the other 5% did something else.
And also there were 36 sleeping passengers.
I don't think you can solve the problem as written.
2007-01-25 06:30:52 · answer #7 · answered by bequalming 5 · 1⤊ 0⤋
95% either accepted or rejected the peanuts
5 % were asleep
5%=36
5% x 20 = 36 x 20
100% = 720 total passengers
^_^
2007-01-25 06:26:29 · answer #8 · answered by Gino R 2 · 0⤊ 1⤋
72%+23% = 95% were asked so 5% were not asked.
So 36 = .05x
x = 36/.05 = 720 persons
Must have been a super jumbo jet.
2007-01-25 06:30:01 · answer #9 · answered by ironduke8159 7 · 0⤊ 1⤋
36/(1-0.72-0.23)
2007-01-25 06:24:47 · answer #10 · answered by Anonymous · 0⤊ 2⤋