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(x-5y)^2

I got

-4y^2

Just wanted to make sure i am right

2007-01-25 06:11:30 · 11 answers · asked by boboby c 1 in Science & Mathematics Mathematics

11 answers

(x-5y)^2 is
x^2+25y^2-10xy

When you have 2 variables in one equation and have square it then we use the formula
(a-b)^2=a^2 + b^2 - 2ab

2007-01-25 06:22:47 · answer #1 · answered by ahsanmohd 2 · 2 0

pls explain how you get the reasult.
Does not make any sense

squaring is pretty straightforward: multiply by itself

(x-5y) (x-5y)= x^2-10xy +25y^2

2007-01-25 14:34:11 · answer #2 · answered by sm bn 6 · 1 0

What are you wanting to do with (x-5y)^2 so that you end up with -4y^2?

Your question doesn't make sense.

2007-01-25 14:22:31 · answer #3 · answered by kindricko 7 · 2 2

sorry man ur answer is not right

(x-5y)(x-5y) = x^2 - 10xy + 25 y^2

2007-01-25 14:27:52 · answer #4 · answered by sakura ♥ 3 · 2 0

x^2 - 10xy + 25y^2

sorry man

try foiling (x-5y)(x-5y)
that is, First times first, outer times outer, inner times inner, last times last, and add these together

2007-01-25 14:23:25 · answer #5 · answered by Gino R 2 · 2 0

What is the question? Where did you get -4y^2 from. What is -4y^2 equal to? Listen to Gino R

2007-01-25 14:23:46 · answer #6 · answered by Rat Boy 2 · 1 2

if you want (x-5y)^2=?
the answer is x^2+25y^2-10xy
1)the answer can't be negative.
2)the answer should have a factor of x^2 too.
(x-5y)(x-5y)=
1)x*x=x^2
+
2)x*(-5y)=-5xy
+

3)(-5y)*x=-5xy
+
4)(-5y)*(-5y)=25y^2
==>x^2-10xy+25y^2

2007-01-25 14:33:45 · answer #7 · answered by rostame_dastan 3 · 1 0

no,you are not right

x^2-10xy+25y^2

when you square you doubled the middle term and square the 2 outer terms

2007-01-25 14:24:03 · answer #8 · answered by Dave aka Spider Monkey 7 · 2 0

You need to multiple each part of the sum by x and then by 5y and add them up.
= x squared -5xy -5xy +25y squared or x squared - 10xy + 25y squared

2007-01-25 14:23:47 · answer #9 · answered by jewelking_2000 5 · 1 2

No sir, you are wrong. The correct answer is

x^2 - 19xy + 25y^2

2007-01-25 14:23:18 · answer #10 · answered by Unknown 2 · 0 3

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