(x-5y)^2 is
x^2+25y^2-10xy
When you have 2 variables in one equation and have square it then we use the formula
(a-b)^2=a^2 + b^2 - 2ab
2007-01-25 06:22:47
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answer #1
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answered by ahsanmohd 2
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pls explain how you get the reasult.
Does not make any sense
squaring is pretty straightforward: multiply by itself
(x-5y) (x-5y)= x^2-10xy +25y^2
2007-01-25 14:34:11
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answer #2
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answered by sm bn 6
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What are you wanting to do with (x-5y)^2 so that you end up with -4y^2?
Your question doesn't make sense.
2007-01-25 14:22:31
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answer #3
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answered by kindricko 7
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sorry man ur answer is not right
(x-5y)(x-5y) = x^2 - 10xy + 25 y^2
2007-01-25 14:27:52
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answer #4
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answered by sakura ♥ 3
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x^2 - 10xy + 25y^2
sorry man
try foiling (x-5y)(x-5y)
that is, First times first, outer times outer, inner times inner, last times last, and add these together
2007-01-25 14:23:25
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answer #5
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answered by Gino R 2
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What is the question? Where did you get -4y^2 from. What is -4y^2 equal to? Listen to Gino R
2007-01-25 14:23:46
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answer #6
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answered by Rat Boy 2
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if you want (x-5y)^2=?
the answer is x^2+25y^2-10xy
1)the answer can't be negative.
2)the answer should have a factor of x^2 too.
(x-5y)(x-5y)=
1)x*x=x^2
+
2)x*(-5y)=-5xy
+
3)(-5y)*x=-5xy
+
4)(-5y)*(-5y)=25y^2
==>x^2-10xy+25y^2
2007-01-25 14:33:45
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answer #7
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answered by rostame_dastan 3
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no,you are not right
x^2-10xy+25y^2
when you square you doubled the middle term and square the 2 outer terms
2007-01-25 14:24:03
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answer #8
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answered by Dave aka Spider Monkey 7
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You need to multiple each part of the sum by x and then by 5y and add them up.
= x squared -5xy -5xy +25y squared or x squared - 10xy + 25y squared
2007-01-25 14:23:47
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answer #9
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answered by jewelking_2000 5
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No sir, you are wrong. The correct answer is
x^2 - 19xy + 25y^2
2007-01-25 14:23:18
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answer #10
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answered by Unknown 2
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