what formulas are needed to answer this question?

Question

a photon is emitted by the flame and has an enerfy of 4.23 X 10 -19 ( thats 10 to the power of -19) Joules. find the a) frequency b) wavelength and c) the portion of the spectrum for this photon. how might you detect this photon?

Answer 1

E= hf where f is the frequency

so f = E/h = 4.2310^(-19)/6.6210^(-34)=6.4 10^14 Hz

Wavelength lambda = c/f =310^8/6.410^14=4.710^-7m = 470 nm

This photon is visible . You can detect it with a spectrophotometer