An 50 proof brandy is 25.0 (v/v) ethyl alcohol. The "proof" is twice the percent concentration of alcohol in the beverage. How many milliliters of alcohol are present in 7.0e+02 mL of brandy?
I have done many percent concentration problems, but this one has confused me. You don't have to do the problem for me, I just need some guidance on how to do it. If anyone could help, I would really appreciate it. Thank you.
2007-01-25 05:40:03 · 2 answers · asked by ash 1 in Science & Mathematics ➔ Chemistry
You already have all the information you need. Since "proof" is double the percentage of alcohol in a mixture, 50 proof means the mixture contains 25% alcohol. So, if you have 7.0e+02 mL = 700mL brandy, 25% of the mixture, or 700 * .25 = 175mL is alcohol.
2007-01-25 05:46:51 · answer #1 · answered by Dan 3 · 0⤊ 0⤋
25% = 1/4
700 mL/4 = 175 mL
2007-01-25 06:56:13 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋