Simplification..imdoomed,..help!?

Question

9n^3(1/3n)^4

simply..stuck

Answer 1

I assume your equation is

9n^3 * (1/(3n))^4 =
9n^3 / (3n)^4 =
9n^3 / 81n^4 =
1/9n

Answer 2

Start by operating on the term in () first:

(1/3n)**4 becomes 1/81n**4 or (n**-4)/81

Then multiply by the other term (multiply or divide coefficients, add or subtract exponents):

9n**3 times (n**-4)/81 becomes (n**-1)/9, or 1/9n

Answer 3

9n³(1/3n)^4 =
9n³(1/81n^4) =
(9 * 1/81)(n³.n^4) =
1/9 * n^7 = n^7 over 9
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Answer 4

I think you are overthinking.

Take it slow.... start with (1/3n)^4

The numerator (top) will be 1^4, which is just 1.
The denominator (bottom) will be (3n)^4.

3^4 is 3x3x3x3 = 81
n^4 is simply written as n^4
These are multiplied, so the denominator is 81n^4

The term (1/3n)^4 then equals (1/81n^4) = top/bottom

Now multiply (9n^3)(1/81n^4)
Top number is (9n^3)(1) = 9n^3
Bottom is still 81n^4

Simplify the number part: (9/81) = 1/9
Simplify the variable part: (n^3/n^4) = (1/n)

These are multiplied together, so your final answer will be
(1/9n)

Answer 5

9n^3 (1/3n)^4
= 9n^3 (1/3)^4 n^4
= 9n^7 (1/81)
= n^7 / 9

Answer 6

9n^3(1/3n)^4
=9n^3 (1^4/(3n)^4)
= 9n^3*(1/81n^4)
= 9n^3/81^4
= 1/ 9n

Answer 7

9 is 3^2

3^2*n^3*3^(-4)*n^4

3^(-2)*n^7

(n^7)/9