You end up with a sound of the same frequency, but with a change in amplitude dependent on the phases of the incoming signals.
You can prove it intuitively easily using Fourier theory... since F[a + b] = F[a] + F[b] (F[.] = Fourier transform of .), then you can't get frequencies in [a + b] that aren't present in [a] or [b], hence you get some scaled version of the frequencies in both F[a] and F[b] (which are the same from your question).
To show it mathematically, I'd use Euler...
Let both signals have frequency = w.
One has phase "p" radians, the other "q" radians:
2cos(wt + p) = exp(j (wt + p) ) + exp(-j (wt + p))
= exp(jp) exp(jwt) + exp(-jp) exp(-jwt)
2cos(wt + q) = exp(jq) exp(jwt) + exp(-jq) exp(-jwt)
2cos(wt + p) + 2cos(wt + q) = [exp(jq) + exp(jp)]exp(jwt) + [exp(-jq) + exp(-jp)]exp(-jwt)
Then, for some A and r that I can't be bothered to work out (you can convert to real/imag parts, add, then go back to polar if you really want):
[exp(jq) + exp(jp)] = A exp(jr)
[exp(-jq) + exp(-jp)] = A exp(-jr)
(you can show yourself that without doing the maths by drawing it in vector form)
...hence...
2cos(wt + p) + 2cos(wt + q) = A exp(jwt + r) + A exp(-jwt - r)
= 2A cos(wt + r)
2007-01-25 11:52:22
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answer #1
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answered by Gavin P 2
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Sound is waves of air pressure. At any point in space and time, they add, either constructively or destructively. Picture the two sources as the center of ripples on a pond. In still, open air, there are places where they are in phase and louder; in other places, they are out of phase and silent. The situation in a room with reflections is more complex.
2007-01-25 09:05:33
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answer #2
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answered by Frank N 7
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The sounds become silent if they are in reverse amplitude but they are with same amplitude then they remain same.
2007-01-25 04:28:36
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answer #3
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answered by rajiv s 1
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If they are synchronize in phase the signal will be stronger, if they are not the signal will be noisy, if the signals are 180° out of phase they will cancel each other.
2007-01-25 04:24:50
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answer #4
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answered by lll 2
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it depends on the phase difference it might produce a constructive interference or negative interference viz it may reinforce the amplitude or nullify it
2007-01-25 08:38:45
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answer #5
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answered by badp 2
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It becomes louder because the amplitudes are added together.
2007-01-25 04:23:28
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answer #6
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answered by M 3
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boom!! it would collide and you would hear a mix of the two sounds. In case of mach speeds, you might hear sonic boom!!
2007-01-25 04:23:38
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answer #7
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answered by Ganesh 2
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clashesssss...thud..thud..thud, u cannot hear anything properly...
2007-01-25 04:19:42
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answer #8
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answered by lakshmi d 2
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