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2007-01-25 03:16:14 · 14 answers · asked by tamdj2001number1 1 in Science & Mathematics Mathematics

14 answers

-4

2007-01-25 03:19:18 · answer #1 · answered by white.sale 3 · 1 0

Simplifying 3x + 2 = 3(5 + x) Reorder the words: 2 + 3x = 3(5 + x) 2 + 3x = (5 * 3 + x * 3) 2 + 3x = (15 + 3x) upload '-3x' to both area of the equation. 2 + 3x + -3x = 15 + 3x + -3x combine like words: 3x + -3x = 0 2 + 0 = 15 + 3x + -3x 2 = 15 + 3x + -3x combine like words: 3x + -3x = 0 2 = 15 + 0 2 = 15 fixing 2 = 15 couldn't come across a variable to unravel for. This equation is invalid, the left and proper aspects aren't any further equivalent, for this reason there is not any answer.

2016-12-03 00:59:10 · answer #2 · answered by ? 4 · 0 0

you need to get the term so that you have all the x's on one side and all the numbers n the other....
3x+5 = x-3 (1st take away x from both sides)
2x+5 = -3 (Then take 5 from both sides)
2x = -8 (Then divide both sides by 2)
x = -4
So x = -4

2007-01-25 03:27:23 · answer #3 · answered by Anonymous · 0 0

3x + 5 = x - 3
Subtract 5 from both sides
3x = x - 8
Subtract x from both sides
2x = - 8
Divide both sides by 2
x = - 4

2007-01-25 03:20:53 · answer #4 · answered by Sheen 4 · 0 0

3x + 5 = x - 3

3x - x = -3 - 5

2x = - 8

x = -8 / 2

x = -4

2007-01-25 03:24:07 · answer #5 · answered by acnemycin 3 · 0 0

x = -4

3x+5=x-3 (subtract x from both sides)
2x+5=-3 (subtract 5 from both sides)
2x=-8 (divide each side by 2)

x=-4

2007-01-25 03:20:11 · answer #6 · answered by mth83vt 4 · 0 0

3x+5= x-3
3x - x = -3 - 5
2x = -8
x = -8 : 2
x = -4
Answer: {x elements of R | x = -4}
:>:

2007-01-25 04:57:40 · answer #7 · answered by aeiou 7 · 0 0

well first combine like terms so you subtract 5 and move it to the right side and subtract x and move it to the left side
so you have..
2x=-8

then you divide both sides by 2 and you get

x=-4

2007-01-25 03:23:54 · answer #8 · answered by Lindsay 3 · 0 0

-4

2007-01-25 03:24:07 · answer #9 · answered by x3_yerr_face_x3 1 · 0 0

-4

2007-01-25 03:19:45 · answer #10 · answered by questionhere 2 · 0 0

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