solve 2^x-1 = 3?

2 ⤊

that is 2 to the power of (x minus 1) = 3

2007-01-25 03:11:25 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

2^(x-1) = 3
ln [2^(x-1)] = ln 3
(x-1)(ln 2) = ln 3
x - 1 = (ln 3)/ln 2)
x = 1 + (ln 3)/(ln 2)

2007-01-25 03:16:57 · answer #1 · answered by Mathematica 7 · 2⤊ 0⤋

2007-01-25 03:18:32 · answer #2 · answered by questionhere 2 · 0⤊ 2⤋

2^x = 3 + 1 = 4 = 2^2
x = 2.

2007-01-25 03:30:30 · answer #3 · answered by steiner1745 7 · 0⤊ 1⤋

2^x = 3 + 1 = 4
ln(2^x) = ln(4)
x len(2) = 2 ln(2)
x = 2

2007-01-25 03:22:54 · answer #4 · answered by Anonymous · 0⤊ 1⤋

2^(x-1) = 3
Log 2^(x-1) = Log 3
(x-1) Log 2 = Log 3
x-1 = Log 3 /Log 2
X = (Log 3/Log 2) + 1

2007-01-25 03:42:37 · answer #5 · answered by dady_mba05 1 · 0⤊ 1⤋